请按照下列要求编写程序。 (1）编写一个Teacher类，包含name和age属性，提供有参构造方法。 (2)在Teacher类中，重写tostring()方法，输出age和name的值。 按年龄升序排列，年龄相同则按名宇升序排列。 "Lucy", "23" "Lily", "25" "Mary". "24" "Lisa". "24" 输出结果 [Person [name=Lucy, age=23], Person [name-Lisa, age=24], Person [name=Mary, age=24], Person [name=Lily, age=25]]

以下是Java代码实现：

import java.util.ArrayList;
import java.util.Collections;
import java.util.Comparator;

class Teacher {
    private String name;
    private int age;

    public Teacher(String name, int age) {
        this.name = name;
        this.age = age;
    }

    @Override
    public String toString() {
        return "Person [name=" + name + ", age=" + age + "]";
    }

    public static void main(String[] args) {
        ArrayList<Teacher> teachers = new ArrayList<>();
        teachers.add(new Teacher("Lucy", 23));
        teachers.add(new Teacher("Lily", 25));
        teachers.add(new Teacher("Mary", 24));
        teachers.add(new Teacher("Lisa", 24));

        Collections.sort(teachers, new Comparator<Teacher>() {
            @Override
            public int compare(Teacher o1, Teacher o2) {
                if (o1.age == o2.age) {
                    return o1.name.compareTo(o2.name);
                }
                return o1.age - o2.age;
            }
        });

        System.out.println(teachers);
    }
}

输出结果为：

[Person [name=Lucy, age=23], Person [name=Lisa, age=24], Person [name=Mary, age=24], Person [name=Lily, age=25]]