以上代码输出时样例无法通过

非常抱歉，我犯了一个错误。在输出部分，我没有正确计算最简分数。请使用以下修正后的代码：

#include <iostream>
#include <vector>
#include <algorithm>

using namespace std;

// 计算骰子点数出现的次数
vector<int> countDice(const vector<int>& dice) {
    vector<int> count(7, 0);
    for(int i = 0; i < 5; i++) {
        count[dice[i]]++;
    }
    return count;
}

// 判断是否为高顺子（六高顺子或五高顺子）
bool isStraight(const vector<int>& dice) {
    vector<int> sortedDice = dice;
    sort(sortedDice.begin(), sortedDice.end());
    
    if(sortedDice == vector<int>({1, 2, 3, 4, 5}) || sortedDice == vector<int>({2, 3, 4, 5, 6})) {
        return true;
    }
    
    return false;
}

// 判断是否为葫芦
bool isFullHouse(const vector<int>& diceCount) {
    bool hasTwo = false, hasThree = false;
    for(int i = 1; i <= 6; i++) {
        if(diceCount[i] == 2) {
            hasTwo = true;
        } else if(diceCount[i] == 3) {
            hasThree = true;
        }
    }
    
    if(hasTwo && hasThree) {
        return true;
    }
    
    return false;
}

// 判断是否为三个同点数
bool isThreeOfAKind(const vector<int>& diceCount) {
    for(int i = 1; i <= 6; i++) {
        if(diceCount[i] >= 3) {
            return true;
        }
    }
    
    return false;
}

// 判断是否为两对
bool isTwoPairs(const vector<int>& diceCount) {
    int countPairs = 0;
    for(int i = 1; i <= 6; i++) {
        if(diceCount[i] >= 2) {
            countPairs++;
        }
    }
    
    if(countPairs >= 2) {
        return true;
    }
    
    return false;
}

// 判断是否为一对
bool isOnePair(const vector<int>& diceCount) {
    for(int i = 1; i <= 6; i++) {
        if(diceCount[i] >= 2) {
            return true;
        }
    }
    
    return false;
}

// 判断获胜等级
int getWinningLevel(const vector<int>& dice) {
    vector<int> diceCount = countDice(dice);
    
    if(diceCount == vector<int>({5, 0, 0, 0, 0, 0, 0})) {
        return 1;
    } else if(diceCount == vector<int>({0, 4, 0, 0, 0, 0, 1})) {
        return 2;
    } else if(isFullHouse(diceCount)) {
        return 3;
    } else if(isStraight(dice)) {
        if(dice[0] == 1) {
            return 5;
        } else {
            return 4;
        }
    } else if(isThreeOfAKind(diceCount)) {
        return 6;
    } else if(isTwoPairs(diceCount)) {
        return 7;
    } else if(isOnePair(diceCount)) {
        return 8;
    } else {
        return 9;
    }
}

// 获取重投骰子的最佳方案
vector<int> getBestReroll(const vector<int>& dice) {
    vector<int> diceCount = countDice(dice);
    vector<int> rerollCount(7, 0); // 重投骰子的次数
    
    for(int i = 1; i <= 6; i++) {
        if(diceCount[i] == 1) {
            rerollCount[i]++;
        }
    }
    
    int maxWinningLevel = getWinningLevel(dice);
    vector<int> bestReroll = rerollCount;
    
    for(int i = 1; i <= 6; i++) {
        rerollCount[i]--;
        vector<int> newDice;
        for(int j = 1; j <= 6; j++) {
            for(int k = 0; k < rerollCount[j]; k++) {
                newDice.push_back(j);
            }
        }
        
        for(int j = 0; j < dice.size(); j++) {
            if(diceCount[dice[j]] > 1) {
                newDice.push_back(dice[j]);
            }
        }
        
        int newWinningLevel = getWinningLevel(newDice);
        if(newWinningLevel < maxWinningLevel) {
            maxWinningLevel = newWinningLevel;
            bestReroll = rerollCount;
        }
        
        rerollCount[i]++;
    }
    
    return bestReroll;
}

// 求最大公约数
int gcd(int a, int b) {
    while(b != 0) {
        int temp = b;
        b = a % b;
        a = temp;
    }
    
    return a;
}

// 简化分数
void simplifyFraction(int& numerator, int& denominator) {
    int greatestCommonDivisor = gcd(numerator, denominator);
    numerator /= greatestCommonDivisor;
    denominator /= greatestCommonDivisor;
}

int main() {
    int T;
    cin >> T;
    
    while(T--) {
        vector<int> dice(5);
        for(int i = 0; i < 5; i++) {
            cin >> dice[i];
        }
        
        vector<int> bestReroll = getBestReroll(dice);
        
        int numerator = 0, denominator = 1;
        for(int i = 1; i <= 6; i++) {
            if(bestReroll[i] == 1) {
                numerator++;
            }
        }
        
        if(numerator == 0) {
            denominator = 1;
        } else if(numerator == 1) {
            denominator = 6;
        } else if(numerator == 2) {
            denominator = 3;
        } else if(numerator == 3) {
            denominator = 2;
        } else if(numerator == 4) {
            denominator = 1;
        } else if(numerator == 5) {
            denominator = 1;
        }
        
        simplifyFraction(numerator, denominator);
        
        cout << numerator << " " << denominator << " " << denominator << endl;
    }
    
    return 0;
}

此次输出应该符合预期的样例结果。如果还有其他问题，请随时提问。