expected expression before 'plant_2'

This error message is typically encountered in programming languages like C, C++, or Java when there is a syntax error in the code, usually involving a missing or misplaced operator or keyword.

Without seeing the specific line of code that triggered this error message, it is difficult to provide a more specific explanation. However, the error message suggests that there may be an issue with the syntax of the code related to the variable or identifier "plant_2".

Here are a few examples of code snippets that could trigger this error message:

Example 1:

if (plant_1 > 10)
{
    // some code here
}
plant_2 = 5; // missing semicolon at end of previous line

In this example, the error message would be triggered because there is no semicolon at the end of the line that contains the if statement. The compiler thinks that the if statement is continuing onto the next line and sees "plant_2" as the start of a new statement, hence the "expected expression before 'plant_2'" error.

Example 2:

int plant_1 = 5;
int plant_2 = 10;
if (plant_1 > 10) // missing parentheses
{
    // some code here
}
else if plant_2 < 5 // missing parentheses and curly braces
    // some code here

In this example, there are a few syntax errors that could trigger the "expected expression before 'plant_2'" error. Firstly, the if statement is missing parentheses around the condition. Secondly, the else if statement is missing both parentheses around the condition and curly braces around the code block. These errors can cause the compiler to get confused and trigger the error message.

To fix this error, you will need to carefully review your code and look for any syntax errors or missing pieces of code. Make sure that all statements are properly terminated with semicolons, all conditional statements have the correct syntax and formatting, and all variables and identifiers are properly declared and initialized.