wr_deadline = wr->xqos->deadline.deadline != DDS_INFINITY;是什么意思
时间: 2024-04-13 10:26:59 浏览: 155
这段代码的意思是判断一个变量`wr_deadline`是否为真。它通过检查`wr`指针所指向的结构体中的`xqos`成员的`deadline`成员是否不等于`DDS_INFINITY`来确定。
更具体地说,它首先访问了`wr`指针所指向的结构体中的`xqos`成员,然后再访问`xqos`成员中的`deadline`成员。如果`deadline`的值不等于`DDS_INFINITY`,那么`wr_deadline`就被设置为真,否则为假。
相关问题
#include <stdio.h> #include <stdlib.h> #define MAX_JOBS 1000 struct job { int deadline; int profit; }; struct set { int parent; int size; }; int find(struct set *sets, int i) { if (sets[i].parent != i) { sets[i].parent = find(sets, sets[i].parent); } return sets[i].parent;} void union_sets(struct set *sets, int x, int y) { int root_x = find(sets, x); int root_y = find(sets, y); if (root_x == root_y) { return; } if (sets[root_x].size < sets[root_y].size) { sets[root_x].parent = root_y; sets[root_y].size += sets[root_x].size; } else { sets[root_y].parent = root_x; sets[root_x].size += sets[root_y].size; } } int cmp_jobs(const void *a, const void *b) { struct job *job_a = (struct job *) a; struct job *job_b = (struct job *) b; return job_b->profit - job_a->profit;} int schedule_jobs(struct job *jobs, int n) { struct set sets[MAX_JOBS+1]; int i, j, max_profit = 0; for (i = 1; i <= n; i++) { sets[i].parent = i; sets[i].size = 1; } qsort(jobs, n, sizeof(struct job), cmp_jobs); for (i = 0; i < n; i++) { int slot = find(sets, jobs[i].deadline); if (slot > 0) { union_sets(sets, slot, slot-1); max_profit += jobs[i].profit; } } return max_profit; } int main() { struct job jobs[] = {{4, 70}, {1, 80}, {1, 30}, {1, 100}}; int n = sizeof(jobs) / sizeof(jobs[0]); int max_profit = schedule_jobs(jobs, n); printf("Max profit: %d\n", max_profit); return 0; }逐句解释这一段代码
这段代码是一个在时间约束下进行任务调度的程序。下面逐句解释:
```c
#include <stdio.h>
#include <stdlib.h>
#define MAX_JOBS 1000
```
这是标准头文件和定义一个宏常量。
```c
struct job {
int deadline;
int profit;
};
```
定义了一个结构体,用于存储任务的截止时间和利润。
```c
struct set {
int parent;
int size;
};
```
定义了一个结构体,用于存储并查集的节点信息。
```c
int find(struct set *sets, int i) {
if (sets[i].parent != i) {
sets[i].parent = find(sets, sets[i].parent);
}
return sets[i].parent;
}
```
定义了一个函数,用于查找并查集中某个节点的根节点。
```c
void union_sets(struct set *sets, int x, int y) {
int root_x = find(sets, x);
int root_y = find(sets, y);
if (root_x == root_y) {
return;
}
if (sets[root_x].size < sets[root_y].size) {
sets[root_x].parent = root_y;
sets[root_y].size += sets[root_x].size;
} else {
sets[root_y].parent = root_x;
sets[root_x].size += sets[root_y].size;
}
}
```
定义了一个函数,用于合并并查集中两个集合。
```c
int cmp_jobs(const void *a, const void *b) {
struct job *job_a = (struct job *) a;
struct job *job_b = (struct job *) b;
return job_b->profit - job_a->profit;
}
```
定义了一个函数,用于比较任务的利润大小。
```c
int schedule_jobs(struct job *jobs, int n) {
struct set sets[MAX_JOBS+1];
int i, j, max_profit = 0;
for (i = 1; i <= n; i++) {
sets[i].parent = i;
sets[i].size = 1;
}
qsort(jobs, n, sizeof(struct job), cmp_jobs);
for (i = 0; i < n; i++) {
int slot = find(sets, jobs[i].deadline);
if (slot > 0) {
union_sets(sets, slot, slot-1);
max_profit += jobs[i].profit;
}
}
return max_profit;
}
```
定义了一个函数,用于进行任务调度,返回最大利润。
```c
int main() {
struct job jobs[] = {{4, 70}, {1, 80}, {1, 30}, {1, 100}};
int n = sizeof(jobs) / sizeof(jobs[0]);
int max_profit = schedule_jobs(jobs, n);
printf("Max profit: %d\n", max_profit);
return 0;
}
```
主函数,定义了一个任务数组,调用任务调度函数,输出最大利润。
<if test="passengerQuery.orderByColumn == null || passengerQuery.orderByColumn == ''||passengerQuery.ascDesc == null || passengerQuery.ascDesc == ''"> order by <if test="passengerQuery.samePhoneNumberTblScmPassengerIds != null and passengerQuery.samePhoneNumberTblScmPassengerIds.size>0"> CASE WHEN id in <foreach collection="passengerQuery.samePhoneNumberTblScmPassengerIds" item="itemCode" index="index" open="(" separator="," close=")"> #{itemCode} </foreach> </if> THEN 0 ELSE 1 END,b.handle_deadline asc,DATE_FORMAT(b.flight_date,'%Y-%m-%d') desc,convert(b.psg_name using gbk),b.id </if>这样写会报错吗?
这段代码存在一些问题,主要是if语句的嵌套和条件判断不完整。具体来说,if语句中缺少一个else分支,另外在第6行缺少一个关闭的标签。正确的代码如下:
```
<if test="passengerQuery.orderByColumn == null || passengerQuery.orderByColumn == ''||passengerQuery.ascDesc == null || passengerQuery.ascDesc == ''">
order by
<if test="passengerQuery.samePhoneNumberTblScmPassengerIds != null and passengerQuery.samePhoneNumberTblScmPassengerIds.size>0">
CASE WHEN id in
<foreach collection="passengerQuery.samePhoneNumberTblScmPassengerIds" item="itemCode" index="index" open="(" separator="," close=")">
#{itemCode}
</foreach>
END,
</if>
b.handle_deadline asc,
DATE_FORMAT(b.flight_date,'%Y-%m-%d') desc,
convert(b.psg_name using gbk),
b.id
</if>
```
这样修改后,就可以避免语法错误了。
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