简易五子棋游戏的软件架构
时间: 2023-08-05 16:08:59 浏览: 44
简易五子棋游戏的软件架构可以分为两层:
1. 用户界面层:用于显示游戏界面,接收用户的输入,并将用户输入转发给游戏逻辑层。用户界面层可以使用简单的控制台窗口实现,如C++中的iostream或Python中的命令行界面。
2. 游戏逻辑层:用于处理游戏逻辑,包括棋局状态的维护、落子规则的判断、胜负判断等。游戏逻辑层需要与用户界面层进行交互,接收用户输入,并将游戏结果返回给用户界面层。游戏逻辑层可以使用面向过程的编程语言实现,如C或Python。
由于简易五子棋游戏的功能较为简单,因此不需要数据存储层和网络通信层等功能的实现。
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java简易五子棋游戏代码
以下是一个简单的 Java 五子棋游戏代码,供参考:
```java
import java.util.Scanner;
public class Gobang {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int[][] board = new int[15][15];
int player = 1;
int row, col;
while (true) {
System.out.print("Player " + player + " make a move (row, col): ");
row = scanner.nextInt();
col = scanner.nextInt();
if (board[row][col] != 0) {
System.out.println("Invalid move, try again.");
continue;
}
board[row][col] = player;
printBoard(board);
if (checkWin(board, row, col, player)) {
System.out.println("Player " + player + " wins!");
break;
}
player = 3 - player; // switch to the other player
}
}
public static void printBoard(int[][] board) {
for (int i = 0; i < 15; i++) {
for (int j = 0; j < 15; j++) {
System.out.print(board[i][j] + " ");
}
System.out.println();
}
}
public static boolean checkWin(int[][] board, int row, int col, int player) {
int count = 0;
// horizontal
for (int j = col - 4; j <= col; j++) {
if (j < 0 || j + 4 >= 15) {
continue;
}
count = 0;
for (int k = 0; k < 5; k++) {
if (board[row][j + k] == player) {
count++;
}
}
if (count == 5) {
return true;
}
}
// vertical
for (int i = row - 4; i <= row; i++) {
if (i < 0 || i + 4 >= 15) {
continue;
}
count = 0;
for (int k = 0; k < 5; k++) {
if (board[i + k][col] == player) {
count++;
}
}
if (count == 5) {
return true;
}
}
// diagonal (top-left to bottom-right)
for (int i = row - 4, j = col - 4; i <= row && j <= col; i++, j++) {
if (i < 0 || j < 0 || i + 4 >= 15 || j + 4 >= 15) {
continue;
}
count = 0;
for (int k = 0; k < 5; k++) {
if (board[i + k][j + k] == player) {
count++;
}
}
if (count == 5) {
return true;
}
}
// diagonal (bottom-left to top-right)
for (int i = row + 4, j = col - 4; i >= row && j <= col; i--, j++) {
if (i >= 15 || j < 0 || i - 4 < 0 || j + 4 >= 15) {
continue;
}
count = 0;
for (int k = 0; k < 5; k++) {
if (board[i - k][j + k] == player) {
count++;
}
}
if (count == 5) {
return true;
}
}
return false;
}
}
```
该代码使用一个二维数组 `board` 表示棋盘,每个空格的值为 0 表示未落子,1 表示黑子,2 表示白子。每个回合轮流由两个玩家输入坐标,在棋盘上落子,然后判断是否有任何一方胜利。`checkWin()` 方法用于检查一个玩家在该回合是否获胜,它依次检查横向、纵向和两个对角线上是否有连续的五颗同色棋子。
简易人机五子棋游戏代码Python
当然可以!以下是一个简易的人机五子棋游戏代码示例(Python):
```python
import random
# 创建棋盘
def create_board():
board = [[' ' for _ in range(15)] for _ in range(15)]
return board
# 打印棋盘
def print_board(board):
print(' 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14')
for i in range(15):
print('{:2d}'.format(i), end=' ')
for j in range(15):
print(board[i][j], end=' ')
print()
# 判断是否胜利
def check_win(board, row,, player):
directions = [(0, 1), (1, 0), (1, 1), (1, -1)]
for d in directions:
count = 1
x, y = row, col
while count < 5:
x += d
y += d
if x < 0 or x >= 15 or y < 0 or y >= 15 or board[x][y] != player:
break
count += 1
x, y = row, col
while count < 5:
x -= d
y -= d
if x < 0 or x >= 15 or y < 0 or y >= 15 or board[x][y] != player:
break
count += 1
if count >= 5:
return True
return False
# 玩家下棋
def player_move(board):
while True:
row = int(input("请输入行号(0-14):"))
col = int(input("请输入列号(0-14):"))
if row >= 0 and row < 15 and col >= 0 and col < 15 and board[row][col] == ' ':
board[row][col] = 'X'
break
else:
print("输入无效,请重新输入!")
# AI下棋
def ai_move(board):
while True:
row = random.randint(0, 14)
col = random.randint(0, 14)
if board[row][col] == ' ':
board[row][col] = 'O'
break
# 游戏主循环
def game_loop():
board = create_board()
print_board(board)
while True:
player_move(board)
print_board(board)
if check_win(board, row, col, 'X'):
print("玩家胜利!")
break
ai_move(board)
print_board(board)
if check_win(board, row, col, 'O'):
print("AI胜利!")
break
# 启动游戏
game_loop()
```
希望这个简易的人机五子棋游戏代码对你有帮助!