SELECT d.areaCode, d.areaName, d.bciStreetName, d.wasteTypeCode, d.wasteTypeName, d.wasteTrashCode, d.wasteTrashName, d.wasteName, sum( p.produceNumTotal ) AS produceNumTotal, sum( IFNULL(t.disposalNumTotal, 0 ),decimal(10,2) ) AS disposalNumTotal, sum( p.cityTransferNum ) AS cityTransferNum, sum( p.transferCityOutNum ) AS transferCityOutNum, sum( p.transferProvinceOutNum ) AS transferProvinceOutNum, sum( IFNULL( p.transferCityOutNum, 0 ) + IFNULL( p.transferProvinceOutNum, 0 ) ) AS transferCityAndProInNum, sum( t.transferCityInNum ) AS transferCityInNum, sum( t.transferProvinceInNum ) AS transferProvinceInNum, sum( IFNULL( t.transferCityInNum, 0 ) + IFNULL( t.transferProvinceInNum, 0 ) ) AS transferCityAndProInNum, sum( d.disposalAmount ) AS disposalAmount, sum( d.zhlyAmount ) AS zhlyAmount, sum( d.czAmount ) AS czAmount, sum( d.zcAmount ) AS zcAmount, sum( d.tmAmount ) AS tmAmount, sum( d.fsAmount ) AS fsAmount, sum( d.qtAmount ) AS qtAmount, CONVERT ( sum( zhlyAmount ) / sum( d.disposalAmount ) * 100, DECIMAL ( 10, 2 ) ) AS zhlyProportion, CONVERT ( sum( tmAmount ) / sum( d.disposalAmount ) * 100, DECIMAL ( 10, 2 ) ) AS tmProportion, CONVERT ( sum( fsAmount ) / sum( d.disposalAmount ) * 100, DECIMAL ( 10, 2 ) ) AS fsProportion, CONVERT ( sum( qtAmount ) / sum( d.disposalAmount ) * 100, DECIMAL ( 10, 2 ) ) AS qtProportion FROM wfcs_disposal_account_day_report d LEFT OUTER JOIN wfcs_transfer_sheet_disposal_day_summary t ON d.cityCode = t.disposalCityCode AND t.tenantId = d.tenantId LEFT OUTER JOIN wfcs_transfer_sheet_produce_day_summary p ON d.cityCode = p.produceCityCode AND d.tenantId = p.tenantId WHERE d.solidWasteType ='ybgygf' AND d.tenantId = '779ca469251e4a639fd39a7ab57e6859' AND d.recordDate >= '2023-06-01 00:00:00.0' AND d.recordDate <= '2023-06-04 00:00:00.0' AND d.cityCode = 'dacef933e39740349e6fb89fac792aae' GROUP BY areaCode ORDER BY produceNumTotal DESC 怎么优化这个sql
时间: 2024-03-07 10:52:06 浏览: 60
这个SQL语句可以进行以下优化:
1. 在wfcs_disposal_account_day_report表中添加索引,包括solidWasteType、tenantId、recordDate和cityCode列,以加快查询速度。
2. 可以考虑使用INNER JOIN代替LEFT OUTER JOIN,因为INNER JOIN在连接两个表的时候比LEFT OUTER JOIN更快。
3. 避免在SELECT语句中使用函数,因为函数会使查询变慢。可以将计算逻辑移至应用程序代码中进行计算。
4. 考虑对查询结果进行缓存,以避免重复查询相同的数据。
5. 可以尝试将GROUP BY子句中的areaCode列替换为更简单的列,以避免在GROUP BY子句中使用太多列。
6. 如果数据量非常大,可以考虑分区表以提高查询性能。
总之,优化SQL查询的方法有很多,需要根据具体情况进行分析和优化。
相关问题
SELECT sum(x.offline = 1) AS deviceoffline , sum(x.offline = 0) AS deviceonline FROM ( SELECT id AS devicecount , TIMESTAMPDIFF(HOUR, `update`, NOW()) > 3 AS offline , uuid FROM `laim_data`.`usedevice` ) x WHERE x.uuid IN ( SELECT uuid FROM `laim_data`.`usedevice` d WHERE d.city IN ( SELECT areacode FROM `laim_data`.`user_area` WHERE user_code = 'test' ) );进行优化
这个SELECT语句可以进行如下优化:
1. 将子查询中的uuid列表提前查询出来,然后在主查询中使用IN语句代替子查询,可以避免重复查询。
2. 将TIMESTAMPDIFF函数中的NOW()提前查询出来,可以避免在每个记录中都重复计算当前时间。
优化后的SQL语句如下:
```
SELECT
SUM(x.offline = 1) AS deviceoffline,
SUM(x.offline = 0) AS deviceonline
FROM (
SELECT
id AS devicecount,
(TIMESTAMPDIFF(HOUR, `update`, now()) > 3) AS offline,
uuid
FROM `laim_data`.`usedevice`
WHERE uuid IN (
SELECT uuid
FROM `laim_data`.`usedevice` d
WHERE d.city IN (
SELECT areacode
FROM `laim_data`.`user_area`
WHERE user_code = 'test'
)
)
) x;
```
这样就可以减少重复查询,提高查询效率。
9.编写一个类,能识别输入的身份证号码对错,该类还有输出省份、出生年月,男女的方法属性
在Java中,你可以创建一个名为`IdentityCardValidator`的类来实现这个功能。首先,你需要了解身份证号码的结构,它通常包含18位数字,分为6个部分:前两个代表行政区划码,接下来的8位代表出生日期,倒数第7位是奇数表示男性,偶数表示女性,最后一位是校验码。
以下是一个基础的实现框架:
```java
import java.time.LocalDate;
public class IdentityCardValidator {
private String idNumber;
// 构造函数接收身份证号码作为参数
public IdentityCardValidator(String id) {
this.idNumber = id;
}
// 验证身份证号码是否有效
public boolean isValid() {
// 省份和出生日期的判断逻辑可以在这里实现,但这里仅作示例
// 如果需要精确验证,需要依赖第三方库或API
// 这里简单假设输入的是18位数字且格式正确
return idNumber.length() == 18;
}
// 获取省份信息
public String getProvince() {
// 这里也需要实际的省份对应规则,此处仅为示例
int areaCode = Integer.parseInt(idNumber.substring(0, 2));
return "省份名" + (areaCode - 1); // 假设每个省的代码减一对应名称
}
// 获取出生年月
public LocalDate getBirthDate() {
int birthYear = Integer.parseInt(idNumber.substring(6, 10));
int birthMonth = Integer.parseInt(idNumber.substring(10, 12)) - 1; // 减一转换成月份
int birthDay = Integer.parseInt(idNumber.substring(12, 14));
return LocalDate.of(birthYear, birthMonth, birthDay);
}
// 判断性别
public char getGender() {
return idNumber.charAt(16) % 2 == 0 ? '女' : '男';
}
// 其他相关方法...
}
// 使用示例
IdentityCardValidator icv = new IdentityCardValidator("123456789012345678");
if (icv.isValid()) {
System.out.println("省份:" + icv.getProvince());
System.out.println("出生日期:" + icv.getBirthDate());
System.out.println("性别:" + icv.getGender());
} else {
System.out.println("身份证号码无效");
}
```
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