c语言实现二叉树不递归中序遍历的代码，请使用链栈

好的，以下是使用链栈实现二叉树不递归中序遍历的代码：

#include <stdio.h>
#include <stdlib.h>

typedef struct TreeNode {
    int val;
    struct TreeNode *left;
    struct TreeNode *right;
} TreeNode;

typedef struct StackNode {
    struct TreeNode *node;
    struct StackNode *next;
} StackNode;

void push(StackNode **top, TreeNode *node) {
    StackNode *newNode = (StackNode *)malloc(sizeof(StackNode));
    newNode->node = node;
    newNode->next = *top;
    *top = newNode;
}

TreeNode *pop(StackNode **top) {
    if (*top == NULL) {
        return NULL;
    }
    StackNode *temp = *top;
    *top = (*top)->next;
    TreeNode *node = temp->node;
    free(temp);
    return node;
}

void inOrderTraversal(TreeNode *root) {
    if (root == NULL) {
        return;
    }
    StackNode *stack = NULL;
    TreeNode *node = root;
    while (node != NULL || stack != NULL) {
        while (node != NULL) {
            push(&stack, node);
            node = node->left;
        }
        node = pop(&stack);
        printf("%d ", node->val);
        node = node->right;
    }
}

int main() {
    TreeNode *root = (TreeNode *)malloc(sizeof(TreeNode));
    root->val = 1;
    root->left = (TreeNode *)malloc(sizeof(TreeNode));
    root->left->val = 2;
    root->left->left = NULL;
    root->left->right = NULL;
    root->right = (TreeNode *)malloc(sizeof(TreeNode));
    root->right->val = 3;
    root->right->left = (TreeNode *)malloc(sizeof(TreeNode));
    root->right->left->val = 4;
    root->right->left->left = NULL;
    root->right->left->right = NULL;
    root->right->right = (TreeNode *)malloc(sizeof(TreeNode));
    root->right->right->val = 5;
    root->right->right->left = NULL;
    root->right->right->right = NULL;

    inOrderTraversal(root);

    return 0;
}

当然，如果您有其它更具体的问题，我也可以继续为您解答。