帮我写一个rust和C语言交互的结构体和接口,rust结构体中有一个字符串和一个LinkedList<String>,填充好数据后传递给C++,然后在C语言中将这个LinkedList<String>转存到std::list中。
时间: 2024-02-23 17:01:57 浏览: 128
字符串大小写交互5.cpp 使用C++实现
好的,首先需要编写一个rust结构体,包含一个字符串和一个LinkedList<String>,如下所示:
```rust
use std::collections::LinkedList;
#[repr(C)]
pub struct RustStruct {
pub s: *const libc::c_char,
pub list: *const LinkedListNode,
}
#[repr(C)]
pub struct LinkedListNode {
pub data: *const libc::c_char,
pub next: *const LinkedListNode,
}
```
然后编写一个初始化RustStruct的函数,如下所示:
```rust
#[no_mangle]
pub extern "C" fn init_rust_struct() -> *const RustStruct {
let s = CString::new("Hello, world!").unwrap();
let mut list = LinkedList::new();
list.push_back(CString::new("Rust").unwrap());
list.push_back(CString::new("C++").unwrap());
let mut nodes = Vec::new();
for item in list.iter() {
let node = Box::new(LinkedListNode {
data: item.as_ptr(),
next: std::ptr::null(),
});
nodes.push(Box::into_raw(node));
}
let mut head = std::ptr::null();
let mut tail = std::ptr::null_mut();
for node in nodes.iter().rev() {
unsafe {
(*node).next = head;
head = (*node);
if tail.is_null() {
tail = node;
}
}
}
let rust_struct = Box::new(RustStruct {
s: s.into_raw(),
list: head,
});
Box::into_raw(rust_struct)
}
```
接下来编写一个用于将LinkedList<String>转换为std::list的函数,如下所示:
```c++
#include <list>
#include <string>
#include "rust_interface.h"
std::list<std::string> convert_linked_list(const RustStruct* rust_struct) {
std::list<std::string> result;
auto node = rust_struct->list;
while (node != nullptr) {
result.push_back(node->data);
node = node->next;
}
return result;
}
```
最后,在Rust中调用这个C++函数来将LinkedList<String>转换为std::list,如下所示:
```rust
#[link(name = "rust_cxx_example")]
extern "C" {
fn convert_linked_list(rust_struct: *const RustStruct) -> List;
}
fn main() {
let rust_struct = init_rust_struct();
let list = unsafe { convert_linked_list(rust_struct) };
for item in list {
println!("{}", item);
}
}
```
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