用c语言编写一个把10进制转为16进制的程序
时间: 2023-06-02 17:02:45 浏览: 107
```c
#include <stdio.h>
int main()
{
int decimal;
printf("请输入一个十进制数:");
scanf("%d", &decimal);
char hexadecimal[100];
int index = 0;
while(decimal != 0)
{
int remainder = decimal % 16;
if(remainder < 10)
{
hexadecimal[index] = remainder + '0';
}
else
{
hexadecimal[index] = remainder - 10 + 'A';
}
decimal /= 16;
index++;
}
printf("转换为十六进制为:");
for(int i = index - 1; i >= 0; i--)
{
printf("%c", hexadecimal[i]);
}
return 0;
}
```
运行结果:
```
请输入一个十进制数:256
转换为十六进制为:100
```
相关问题
用c语言编写一个,10进制转为16进制的程序,包括小数部分
以下是一个将十进制数转换为十六进制数的C程序,如果需要转换的数字是小数,则输出在十六进制下的近似值:
```
#include <stdio.h>
#include <math.h>
int main(void) {
double dec, frac;
int i, j;
char hex[20];
printf("Enter a decimal number: ");
scanf("%lf", &dec);
i = (int) dec;
frac = dec - i;
// 将整数部分转换为十六进制
j = 0;
while (i != 0) {
int remainder = i % 16;
if (remainder < 10) {
hex[j++] = 48 + remainder;
} else {
hex[j++] = 55 + remainder;
}
i /= 16;
}
// 反转整数部分得到正确的十六进制
printf("Hexadecimal equivalent of %lf: 0x", dec);
for (int k = j - 1; k >= 0; k--) {
printf("%c", hex[k]);
}
// 如果有小数部分,将它转换为十六进制
if (frac != 0.0) {
printf(".");
// 显示小数部分的前八位
for (int l = 0; l < 8; l++) {
frac *= 16;
int digit = (int) frac;
if (digit < 10) {
printf("%c", 48 + digit);
} else {
printf("%c", 55 + digit);
}
frac -= digit;
}
}
printf("\n");
return 0;
}
```
这个程序首先获取需要转换的十进制数并将其分为整数和小数两部分。然后,它将整数部分转换为十六进制,并反转字符串以得到正确的代码。最后,如果有小数部分,则将它转换为十六进制,并输出在小数点前添加一个“.”的格式下的结果。
用c语言编写一个把10进制小数转为16进制小数的程序
#include <stdio.h>
int main() {
double num;
printf("请输入一个10进制小数:");
scanf("%lf", &num);
// 将小数部分转为16进制
printf("16进制小数为:0x");
for (int i = 0; i < 8; i++) {
num *= 16;
int digit = (int)num;
num -= digit;
printf("%X", digit);
}
printf("\n");
return 0;
}
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