rapidjson 合成{"s":["lie","swh","bgss","swi","fa","cc"],"se":["me","sch","briess","sh1","fe","ct"]} ,PushBack函数第一个参数是CString
时间: 2023-08-10 18:04:06 浏览: 52
如果你希望使用RapidJSON将一个CString数组合成为JSON字符串 `{"s":["lie","swh","bgss","swi","fa","cc"],"se":["me","sch","briess","sh1","fe","ct"]}`,你可以按照以下步骤进行操作:
```cpp
#include <iostream>
#include "rapidjson/document.h"
#include "rapidjson/writer.h"
#include "rapidjson/stringbuffer.h"
using namespace rapidjson;
int main() {
// 创建一个空的Document对象
Document document;
document.SetObject();
// 创建并设置CString数组s
Value s(kArrayType);
s.PushBack("lie", document.GetAllocator());
s.PushBack("swh", document.GetAllocator());
s.PushBack("bgss", document.GetAllocator());
s.PushBack("swi", document.GetAllocator());
s.PushBack("fa", document.GetAllocator());
s.PushBack("cc", document.GetAllocator());
// 创建并设置CString数组se
Value se(kArrayType);
se.PushBack("me", document.GetAllocator());
se.PushBack("sch", document.GetAllocator());
se.PushBack("briess", document.GetAllocator());
se.PushBack("sh1", document.GetAllocator());
se.PushBack("fe", document.GetAllocator());
se.PushBack("ct", document.GetAllocator());
// 将数组s和se添加到document中
document.AddMember("s", s, document.GetAllocator());
document.AddMember("se", se, document.GetAllocator());
// 创建一个StringBuffer来存储JSON字符串
StringBuffer buffer;
Writer<StringBuffer> writer(buffer);
document.Accept(writer);
// 将StringBuffer转换为std::string并输出
std::string jsonStr = buffer.GetString();
std::cout << jsonStr << std::endl;
return 0;
}
```
在上面的代码中,我们首先创建一个空的`Document`对象。然后,我们创建一个数组`s`并添加了一些CString元素。接下来,我们创建另一个数组`se`并添加了一些CString元素。最后,我们将这两个数组作为成员添加到`document`中。然后,我们使用`StringBuffer`和`Writer`将`document`转换为JSON字符串,并将其输出。
运行上述代码,你将得到输出的JSON字符串:
```
{"s":["lie","swh","bgss","swi","fa","cc"],"se":["me","sch","briess","sh1","fe","ct"]}
```
希望这个示例对你有帮助!如果有任何疑问,请随时提问。