for(i=1;i<=9;i++)
时间: 2023-12-30 17:06:47 浏览: 26
This code snippet seems to have an error. The third parameter in the for loop is missing.
Assuming the missing parameter is incrementing the value of i by 1, the corrected code would be:
for (i = 1; i <= 9; i++) {
// code to be executed in each iteration of the loop
}
This loop will execute the code block for values of i from 1 to 9, incrementing i by 1 in each iteration.
相关问题
int+i,+s+=+0;+for(i+=+1;+i+<+10;+i+=+i+++2){+s+=+s+++i;
int i, s = 0; for(i = 1; i < 10; i = i + 2){ s = s + i; }
在这段代码中,变量i的初始值为1,每次循环i都会增加2。循环的条件是i < 10,所以当i的值等于9时,循环结束。在每次循环中,变量s会将当前的i值累加到自身。最终结果是s等于1 + 3 + 5 + 7 + 9,即25。
int+i,+sum+=+0; for+(+i+=+1;+i+<+8;+i+++)+{ +++if+(+i%2+==+0+)+{ +++++++continue; +++} +++sum+=+sum
根据提供的引用内容,以下是两种不同语言的代码示例:
1. C语言代码示例:
```c
#include<stdio.h>
int main() {
int i;
int sum=0;
for(i=1;i<=4;i++)
sum=sum+i;
printf("sum=%d\n",sum);
return 0;
}
```
2. Java代码示例:
```java
public class Main {
public static void main(String[] args) {
int[] arrayList = new int[20];
int sum = 0;
for(int i=0; i<=19; i++)
arrayList[i] = i+1;
int pos = 0; while(pos<20){
if(arrayList[pos]%2 == 0)
continue;
sum = sum + arrayList[pos];
pos++;
}
System.out.println("sum="+sum);
}
}
```
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