变异凯撒解码python

变异凯撒解码是一种根据给定的偏移量对密文进行解密的方法。根据引用中的代码，我们可以使用以下Python代码来进行变异凯撒解码:

str = 'afZ_r9VYfScOeO_UL^RWUc'
k = 5
for i in str:
    asc = ord(i) - k
    asc = chr(asc)
    print(asc,end="")
    k = k + 1 

这段代码将逐个字符转换为ASCII码，然后根据偏移量将ASCII码减去相应的值。最后再将ASCII码转换回字符，并打印出来。通过这个过程，我们可以解码出变异凯撒密码的原文。<em>1</em><em>2</em><em>3</em>
#### 引用[.reference_title]
- *1* [CTF凯撒密码解密Python脚本](https://blog.csdn.net/u010508029/article/details/90294146)[target="_blank" data-report-click={"spm":"1018.2226.3001.9630","extra":{"utm_source":"vip_chatgpt_common_search_pc_result","utm_medium":"distribute.pc_search_result.none-task-cask-2~all~insert_cask~default-1-null.142^v92^chatsearchT3_1"}} ] [.reference_item]
- *2* [凯撒加密算法--python](https://blog.csdn.net/m0_59882269/article/details/120956253)[target="_blank" data-report-click={"spm":"1018.2226.3001.9630","extra":{"utm_source":"vip_chatgpt_common_search_pc_result","utm_medium":"distribute.pc_search_result.none-task-cask-2~all~insert_cask~default-1-null.142^v92^chatsearchT3_1"}} ] [.reference_item]
- *3* [BUUCTF 变异凯撒1 python做题记录](https://blog.csdn.net/weixin_56375405/article/details/125959916)[target="_blank" data-report-click={"spm":"1018.2226.3001.9630","extra":{"utm_source":"vip_chatgpt_common_search_pc_result","utm_medium":"distribute.pc_search_result.none-task-cask-2~all~insert_cask~default-1-null.142^v92^chatsearchT3_1"}} ] [.reference_item]
[ .reference_list ]