'generator' object has no attribute 'isin'

引用\[2\]中的代码中出现了一个错误：'generator' object has no attribute 'next'。这个错误是因为在Python 3中，生成器对象的next()方法已经被__next__()方法取代了。所以，正确的调用方式应该是使用__next__()方法来获取生成器对象的下一个元素。修改代码如下所示：

# 定义生成器函数
def liebiao():
    for x in range(10):
        yield x

# 函数调用
g = liebiao()

# 打印元素
print(g.__next__())

这样就可以正确地获取生成器对象的下一个元素了。
#### 引用[.reference_title]
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