Python井字棋游戏代码

以下是Python井字棋游戏代码：

def winner(board):
    # 判断所给棋子是否获胜
    _to_win = {(0,1,2),(3,4,5),(6,7,8),(0,3,6),(1,4,7),(2,5,8),(0,4,8),(2,4,6)}
    for r in _to_win:
        if board[r[0]] == board[r[1]] == board[r[2]]:
            return True
    return False

def dis_board(board):
    # 显示出棋盘
    print("\t{0} | {1} | {2}".format(board[0], board[1], board[2]))
    print("\t_ | _ | _")
    print("\t{0} | {1} | {2}".format(board[3], board[4], board[5]))
    print("\t_ | _ | _")
    print("\t{0} | {1} | {2}".format(board[6], board[7], board[8]))

def tic_tac_toe():
    # 初始化棋盘
    board = list("012345678")
    # 初始化玩家
    player = "X"
    # 初始化步数
    step = 0
    # 游戏开始
    while True:
        # 显示棋盘
        dis_board(board)
        # 玩家输入位置
        move = input("Player {0}, please enter a move (0-8): ".format(player))
        # 判断输入是否合法
        if move not in board:
            print("Invalid move, please try again.")
            continue
        # 更新棋盘
        board[int(move)] = player
        # 判断是否获胜
        if winner(board):
            dis_board(board)
            print("Player {0} wins!".format(player))
            break
        # 判断是否平局
        step += 1
        if step == 9:
            dis_board(board)
            print("It's a tie!")
            break
        # 切换玩家
        player = "O" if player == "X" else "X"

tic_tac_toe()