a={'Mike':90,'Mark':91,'Amy':89} sorted_scores = sorted(a.items(), key=lambda x: (x[0], -x[1]))
时间: 2024-01-24 07:04:31 浏览: 15
This code sorts the dictionary 'a' by the keys in ascending order and the values in descending order. The result is a list of tuples containing the key-value pairs in the sorted order.
For example, if we print the sorted_scores list, we will get:
[('Amy', 89), ('Mark', 91), ('Mike', 90)]
This means that the key 'Amy' has the lowest score (89), followed by 'Mark' with a score of 91, and 'Mike' with a score of 90. If two keys have the same score, they are sorted alphabetically.
相关问题
a={'Mike':90,'Mark':91,'Amy':89} sorted_scores = sorted(a.items(), key=lambda x: (x[0], -x[1])) print(sorted_scores)
The output of the code will be:
[('Amy', 89), ('Mark', 91), ('Mike', 90)]
Explanation:
- The dictionary 'a' contains three key-value pairs representing the scores of three students.
- The 'sorted' function is used to sort the dictionary by the keys and the values.
- The 'items' method is used to convert the dictionary into a list of tuples where each tuple contains the key-value pair.
- The 'key' argument of the 'sorted' function is set to a lambda function that takes a tuple as input and returns a tuple of two values. The first value is the key itself (i.e., the name of the student), and the second value is the negative of the score. The negative is used to sort the scores in descending order.
- The resulting list of tuples is stored in the 'sorted_scores' variable and printed to the console.
rank = sorted(scores.items(), key=lambda x: x[1], reverse=True)
这段代码是用于对每个节点的影响力评分进行排序的。具体来说,它首先使用Python内置的sorted()方法对scores字典中的项进行排序,按照每个项的值(即影响力评分)进行降序排列,保存在名为rank的列表中。该列表的每个元素都是一个二元组,第一个元素为节点编号,第二个元素为影响力评分。
sorted()方法的第二个参数是一个函数,用于指定排序的依据。在这里,我们使用了Python的lambda表达式,指定按照每个项的第二个元素(即x[1])进行排序。由于需要按照降序排列,我们还指定了reverse=True参数。
排序后,rank列表中的每个元素就代表了每个节点的影响力评分,按照从高到低的顺序排列。我们可以使用该列表进行后续的分析、可视化等操作。
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