再换一个吧
时间: 2024-02-24 13:55:05 浏览: 18
好的,我再提供一个Python小游戏,叫做“2048游戏”:
```python
import random
# 定义游戏板
board = [[0] * 4 for i in range(4)]
# 定义游戏状态
status = "continue"
# 定义得分
score = 0
# 随机生成两个数字
def generate():
x = random.randint(0, 3)
y = random.randint(0, 3)
while board[x][y] != 0:
x = random.randint(0, 3)
y = random.randint(0, 3)
board[x][y] = 2
# 显示游戏板
def display():
for i in range(4):
for j in range(4):
print(board[i][j], end="\t")
print()
print("得分:%d" % score)
# 合并数字
def merge(nums):
i = 0
while i < len(nums) - 1:
if nums[i] == nums[i + 1]:
nums[i] *= 2
nums.pop(i + 1)
nums.append(0)
global score
score += nums[i]
i += 1
# 向左移动
def move_left():
global board
for i in range(4):
merge(board[i])
# 向右移动
def move_right():
global board
for i in range(4):
merge(board[i][::-1])
board = [row[::-1] for row in board]
# 向上移动
def move_up():
global board
for i in range(4):
nums = [board[j][i] for j in range(4)]
merge(nums)
for j in range(4):
board[j][i] = nums[j]
# 向下移动
def move_down():
global board
for i in range(4):
nums = [board[j][i] for j in range(4)][::-1]
merge(nums)
for j in range(4):
board[j][i] = nums[::-1][j]
# 判断游戏是否结束
def is_over():
for i in range(4):
for j in range(3):
if board[i][j] == 0 or board[i][j] == board[i][j + 1]:
return False
for i in range(3):
for j in range(4):
if board[i][j] == board[i + 1][j]:
return False
return True
# 开始游戏
generate()
generate()
display()
while status == "continue":
direction = input("请输入移动方向(l/r/u/d):")
if direction == "l":
move_left()
elif direction == "r":
move_right()
elif direction == "u":
move_up()
elif direction == "d":
move_down()
else:
print("非法输入,请重新输入!")
continue
generate()
display()
if is_over():
status = "gameover"
print("游戏结束!得分:%d" % score)
```
这个游戏的规则是:程序会生成一个4x4的游戏板,最开始会随机生成两个数字(2或4),玩家需要通过输入移动方向(上下左右)来合并相同数字,直到游戏板上没有空位或者无法再合并数字。每次合并会得到一定的分数。如果游戏板上没有空位且无法再合并数字,游戏结束,显示得分。
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