优化这段代码@Select("SELECT SUM(CASE WHEN MONTH(registerTime) =1 THEN 1 ELSE 0 END) 一月, SUM(CASE WHEN MONTH(registerTime) =2 THEN 1 ELSE 0 END) 二月,\n" + "SUM(CASE WHEN MONTH(registerTime) =3 THEN 1 ELSE 0 END) 三月, SUM(CASE WHEN MONTH(registerTime) =4 THEN 1 ELSE 0 END) 四月,\n" + "SUM(CASE WHEN MONTH(registerTime) =5 THEN 1 ELSE 0 END) 五月, SUM(CASE WHEN MONTH(registerTime) =6 THEN 1 ELSE 0 END) 六月,\n" + "SUM(CASE WHEN MONTH(registerTime) =7 THEN 1 ELSE 0 END) 七月, SUM(CASE WHEN MONTH(registerTime) =8 THEN 1 ELSE 0 END) 八月,\n" + "SUM(CASE WHEN MONTH(registerTime) =9 THEN 1 ELSE 0 END) 九月, SUM(CASE WHEN MONTH(registerTime) =10 THEN 1 ELSE 0 END) 十月,\n" + "SUM(CASE WHEN MONTH(registerTime) =11 THEN 1 ELSE 0 END) 十一月, SUM(CASE WHEN MONTH(registerTime) =12 THEN 1 ELSE 0 END) 十二月\n" + "FROM(select DISTINCT contactName,phone,dataRole,typename,regionUid,region,provinceUid,province,address,registerTime\n" + "from (select `user`.uid as customerUid, `user`.contactName, `user`.phone, `user`.dataRole, `user`.typename, `user`.address, \n" + "`user`.registerTime,`user`.provinceUid,`user`.regionUid,`user`.sn, region.region, province.province from region, province, (\n" + "select `user`.*, ma.sn from `user` left join (select * from machine_customer where deleted = 0) ma on `user`.uid = ma.customerUid where \n" + "`user`.deleted = 0) `user` where region.uid=`user`.regionUid and province.uid=`user`.provinceUid) `user`) `user` WHERE registerTime LIKE CONCAT('%',#{year},'%')") Map<String, Integer> selectCustomerByYear(String year);

1 select 2 sum(case month(r_time) when '1' then r_recharge else 0 end) as Jan, 3 sum(case month(r_time) when '2' then r_recharge else 0 end) as Feb, 4 sum(case month(r_time) when '3' then r_recharge else 0 end) as Mar, 5 sum(case month(r_time) when '4' then r_recharge else 0 end) as Apr, 6 sum(case month(r_time) when '5' then r_recharge else 0 end) as May, 7 sum(case month(r_time) when '6' then r_recharge else 0 end) as June, 8 sum(case month(r_time) when '7' then r_recharge else 0 end) as July, 9 sum(case month(r_time) when '8' then r_recharge else 0 end) as Aug, 10 sum(case month(r_time) when '9' then r_recharge else 0 end) as Sept, 11 sum(case month(r_time) when '10' then r_recharge else 0 end) as Oct, 12 sum(case month(r_time) when '11' then r_recharge else 0 end) as Nov, 13 sum(case month(r_time) when '12' then r_recharge else 0 end) as Dece 14 from rechargeinfo 15 where year(r_time)='2019';

这是一个 SQL 查询语句，用于计算2019年每个月的充值总额。在rechargeinfo表中，使用r_time字段获取每个月的充值金额，并将结果存储在对应的月份列中。最后，使用WHERE子句筛选出2019年的数据。请注意，这只是一个...

select a.id,SUM(CASE WHEN d.shoukuan_month = '2023-05' and d.is_del = 0 then d.netincome ELSE 0 end) as one_shoukuan,SUM(CASE WHEN d.shoukuan_month = '2023-04' AND d.is_del = 0 THEN d.netincome ELSE 0 END) as two_shoukuan,(CASE WHEN b.month = '2023-05' THEN b.create_income ELSE 30000 END) as one_income,(CASE WHEN b.month = '2023-04' THEN b.create_income ELSE 30000 END) as two_income from a left join b on b.kefuid = a.id left join d on d.kefuid = a.id where a.brand = '1' and a.is_del = 0 and a.is_lizhi = 0 group by a.id这个sql如何让select 中的d.one_shoukuan >= b.one_income and d.two_shoukuan >= b.two_income这个多个join会导致sum多次循环导致sum不断叠加

你可以在外层使用HAVING子句来过滤... AND SUM(CASE WHEN d.shoukuan_month = '2023-04' AND d.is_del = 0 THEN d.netincome ELSE 0 END) >= (CASE WHEN b.month = '2023-04' THEN b.create_income ELSE 30000 END)

select (CASE WHEN b.month = '2023-05' THEN b.create_income ELSE 0 END) as two_income from a left join b on b.kefuid = a.id left join d on d.kefuid = a.id where a.brand = '16' and a.is_del = 0 and a.is_lizhi = 0 group by a.id limit 1;必须要通过sum才能正确的输出case when

select sum(CASE WHEN b.month = '2023-05' THEN b.create_income ELSE 0 END) as two_income from a left join b on b.kefuid = a.id left join d on d.kefuid = a.id where a.brand = '16' and a.is_del = 0 and a...

SELECT a.username, a.userid, a.orgname, a.orgnamehr orgnameHr, a.company company, a.idcard, sum(CASE a.hour_type WHEN 'A' THEN a.allot_hour ELSE 0 END ) aHour, sum(CASE a.hour_type WHEN 'B' THEN a.allot_hour ELSE 0 END ) bHour, sum(CASE a.hour_type WHEN 'C' THEN a.allot_hour ELSE 0 END ) cHour, sum(CASE a.hour_type WHEN 'D' THEN a.allot_hour ELSE 0 END ) dHour, sum(CASE a.hour_type WHEN 'E' THEN a.allot_hour ELSE 0 END ) eHour, sum(CASE a.hour_type WHEN 'F' THEN a.allot_hour ELSE 0 END ) fHour, sum(CASE WHEN a.hour_type IN ('A','B','C','D','E','F') THEN a.allot_hour ELSE 0 END ) countHour, CASE yearMonth WHEN CONVERT(varchar(10), d.break_sure_date, 23) >= CONVERT(varchar(10),'2023-06-06', 23) and CONVERT(varchar(10), d.break_sure_date, 23) < CONVERT(varchar(10),'2023-07-06', 23) THEN '1' ELSE '2' END FROM ems_hour_allot a

这是一个SQL查询语句，用于从ems_hour_allot表中检索数据。查询结果将包括以下列：username、userid、orgname、orgnameHr、company、idcard、aHour、bHour、cHour、dHour、eHour、fHour、...

SELECT SUM(order_amount) AS total_order_amount, COUNT() AS total_order_count, SUM(CASE WHEN order_time >= 'yyyy-mm-01'::date AND order_time < ('yyyy-mm-01'::date + INTERVAL '1 month') THEN order_amount ELSE 0 END) AS order_amount_month, SUM(CASE WHEN order_time >= 'yyyy-01-01'::date AND order_time < ('yyyy-01-01'::date + INTERVAL '1 year') THEN order_amount ELSE 0 END) AS order_amount_year, SUM(CASE WHEN order_time >= 'yyyy-01-01'::date AND order_time < ('yyyy-01-01'::date + INTERVAL '1 year') THEN 1 ELSE 0 END) AS order_count_year FROM ( SELECT FROM order_1 WHERE member_id = :memberId AND order_time >= 'yyyy-01-01'::date UNION ALL SELECT * FROM order_2 WHERE member_id = :memberId AND order_time >= 'yyyy-01-01'::date UNION ALL SELECT * FROM order_3 WHERE member_id = :memberId AND order_time >= 'yyyy-01-01'::date ) AS all_orders

这是一个 SQL 查询语句，...这个查询语句通过 UNION ALL 将三张订单表合并，并且使用 CASE WHEN 判断订单的时间范围，然后进行相应的求和操作。其中，:memberId 是一个占位符，需要传入具体的会员 ID 才能完成查询。

select a.id,b.is_manager_big, b.is_manager_bcompany,a.one_shoukuan,a.two_shoukuan,b.one_income,b.two_income from (select a.id, SUM(CASE WHEN b.shoukuan_month = '2023-05' and b.is_del = 0 then b.netincome ELSE 0 end) as one_shoukuan, SUM(CASE WHEN b.shoukuan_month = '2023-04' AND b.is_del = 0 THEN b.netincome ELSE 0 END) as two_shoukuan from xw_kefu a left join xw_user_applyloan_checking b on b.kefuid = a.id where a.id in (1748,1749,1776,1834,1913,1921,1922,1778,1830,1829,1833,1835,1750,1753,1754,1756,1758,1761,1892,1905,1762,1764,1902,1915,1751,1773,1792,1774,1788,1917,1791,1793,1795,1909,1775,1787,1752,1757,1771,1772,1914,1768,1898,1760,1767,1769,1863,1770,1827) and a.is_del = 0 and a.is_lizhi = 0 group by a.id) as a,(select a.id,a.is_manager_big, a.is_manager_bcompany, SUM(CASE WHEN b.month = '2023-05' then b.create_income end) as one_income, SUM(CASE WHEN b.month = '2023-04' THEN b.create_income END) as two_income from xw_kefu a left join xw_kefu_performance_target b on b.kefuid = a.id where a.id in (1748,1749,1776,1834,1913,1921,1922,1778,1830,1829,1833,1835,1750,1753,1754,1756,1758,1761,1892,1905,1762,1764,1902,1915,1751,1773,1792,1774,1788,1917,1791,1793,1795,1909,1775,1787,1752,1757,1771,1772,1914,1768,1898,1760,1767,1769,1863,1770,1827) and a.is_del = 0 and a.is_lizhi = 0 group by a.id ) as b where b.id = a.id group by a.id优化一下这个查询统计

WHEN b.shoukuan_month = '2023-05' AND b.is_del = 0 THEN b.netincome ELSE 0 END) AS one_shoukuan, SUM(CASE WHEN b.shoukuan_month = '2023-04' AND b.is_del = 0 THEN b.netincome ELSE 0 END) AS two_...

帮我解析一下这个java错误，Caused by: org.h2.jdbc.JdbcSQLSyntaxErrorException: Syntax error in SQL statement "SELECT C.PERIOD_NO, C.BILL_MONTH, C.LOCAL_AIR_CODE, C.INT_DOM_INDICATOR, 'GLOBAL' AS CHECK_CODE, CASE WHEN COUPON_COUNT_GLOBAL = COUPON_COUNT_REPORT AND TAX_AMT_GLOBAL = TAX_AMT_REPORT AND ISC_AMT_GLOBAL = ISC_AMT_REPORT AND UATP_AMT_GLOBAL = UATP_AMT_REPORT AND GROSS_AMT_GLOBAL = GROSS_AMT_REPORT THEN 'S' ELSE 'F' END AS CHECK_RESULT_IND, TAX_AMT_GLOBAL AS TAX_AMT_ACTUAL, TAX_AMT_REPORT AS TAX_AMT_EXPECTED, ISC_AMT_GLOBAL AS ISC_AMT_ACTUAL, ISC_AMT_REPORT AS ISC_AMT_EXPECTED, UATP_AMT_GLOBAL AS UATP_AMT_ACTUAL, UATP_AMT_REPORT AS UATP_AMT_EXPECTED, GROSS_AMT_GLOBAL AS GROSS_AMT_ACTUAL, GROSS_AMT_REPORT AS GROSS_AMT_EXPECTED, COUPON_COUNT_GLOBAL AS COUPON_COUNT_ACTUAL, COUPON_COUNT_REPORT AS COUPON_COUNT_EXPECTED FROM ( ( SELECT BILL_MONTH, PERIOD_NO, LOCAL_AIR_CODE, INT_DOM_INDICATOR, SUM(COUPON_COUNT) AS COUPON_COUNT_GLOBAL, CASE WHEN SUM(GROSS_AMT_BILLING) IS NULL THEN 0 ELSE SUM(GROSS_AMT_BILLING) END AS GROSS_AMT_GLOBAL, CASE WHEN SUM(BILL_TAX_BILLING) IS NULL THEN 0 ELSE SUM(BILL_TAX_BILLING) END AS TAX_AMT_GLOBAL, CASE WHEN SUM(ISC_AMT_BILLING) IS NULL THEN 0 ELSE SUM(ISC_AMT_BILLING) END AS ISC_AMT_GLOBAL, CASE WHEN SUM(UATP_AMT_BILLING) IS NULL THEN 0 ELSE SUM(UATP_AMT_BILLING) END AS UATP_AMT_GLOBAL FROM OWB_GLOBAL_REPORT WHERE REPORT_TYPE = 'R' AND DELETE_IND IS NULL AND PERIOD_NO = ? AND BILL_MONTH = ? AND INT_DOM_INDICATOR = ? AND LOCAL_AIR_CODE = ? GROUP BY BILL_MONTH, PERIOD_NO, LOCAL_AIR_CODE, INT_DOM_INDICATOR) C[*] INNER JOIN ( SELECT BILL_MONTH, PERIOD_NO, LOCAL_AIR_CODE, INT_DOM_INDICATOR, SUM(COUPON_COUNT) AS COUPON_COUNT_REPORT, CASE WHEN SUM(GROSS_AMT_BILLING) IS NULL THEN 0 ELSE SUM(GROSS_AMT_BILLING) END AS GROSS_AMT_REPORT, CASE WHEN SUM(BILL_TAX_BILLING) IS NULL THEN 0 ELSE SUM(BILL_TAX_BILLING) END AS TAX_AMT_REPORT, CASE WHEN SUM(ISC_AMT_BILLING) IS NULL THEN 0 ELSE SUM(ISC_AMT_BILLING) END AS ISC_AMT_REPORT, CASE WHEN SUM(UATP_AMT_BILLING) IS NULL THEN 0 ELSE SUM(UATP_AMT_BILLING) END AS UATP_AMT_REPORT FROM OWB_REPORT WHERE ADJ_MONTH IS NULL AND PERIOD_NO = ? AND BILL_MONTH = ? AND INT_DOM_INDICATOR = ? AND LOCAL_AIR_CODE = ? GROUP BY BILL_MONTH, PERIOD_NO, LOCAL_AIR_CODE, INT_DOM_INDICATOR) R ON C.BILL_MONTH = R.BILL_MONTH AND C.PERIOD_NO = R.PERIOD_NO AND C.LOCAL_AIR_CODE = R.LOCAL_AIR_CODE AND C.INT_DOM_INDICATOR = R.INT_DOM_INDICATOR )"; expected "UNION, EXCEPT, MINUS, INTERSECT, ORDER, OFFSET, FETCH, LIMIT, SAMPLE_SIZE, FOR, )";

这个错误是由于Java程序中的SQL语句存在语法错误导致的。根据错误信息，语法错误出现在SQL查询语句的最后部分。错误提示指出在预期的位置上应该是"UNION, EXCEPT, MINUS, INTERSECT, ORDER, OFFSET, FETCH, LIMIT, ...

WITH all_orders AS ( SELECT A .create_time AS TIME, A.paid_amount AS amount, 'flower_t_order' AS order_table_name FROM flower_t_order A WHERE A.member_id = 1 AND EXTRACT ( YEAR FROM A.create_time ) = 2023 UNION ALL SELECT B.create_time AS TIME, B.paid_amount AS amount, 'shop_t_order' AS order_table_name FROM shop_t_order B WHERE B.member_id = 1 AND EXTRACT ( YEAR FROM B.create_time ) = 2023 UNION ALL SELECT C .create_time AS TIME, C.paid_amount AS amount, 'ticket_t_order' AS order_table_name FROM ticket_t_order C WHERE C.member_id = 1 AND EXTRACT ( YEAR FROM b.create_time ) = 2023 ) SELECT EXTRACT ( MONTH FROM all_orders."time" ( TIMESTAMP ) ) AS MONTH, SUM ( all_orders.amount ) AS total_order_amount, COUNT ( * ) AS total_order_count, SUM ( CASE WHEN order_table_name = 'flower_t_order' THEN paid_amount ELSE 0 END ) AS order_table_1_amount, SUM ( CASE WHEN order_table_name = 'shop_t_order' THEN paid_amount ELSE 0 END ) AS order_table_2_amount, SUM ( CASE WHEN order_table_name = 'ticket_t_order' THEN paid_amount ELSE 0 END ) AS order_table_3_amount FROM all_orders GROUP BY MONTH ORDER BY MONTH;

SUM ( CASE WHEN order_table_name = 'flower_t_order' THEN paid_amount ELSE 0 END ) AS order_table_1_amount, SUM ( CASE WHEN order_table_name = 'shop_t_order' THEN paid_amount ELSE 0 END ) AS order_...

SELECT t1.id, t1.[gf] AS '供方', t1.[htmc] AS '合同名称', t1.[htbh] AS '合同编号', t1.[sjbh] AS '编号', t1.[qdrq] AS '签订日期', t1.[qsrq] AS '起始日期', t1.[jzrq] AS '截止日期', t1.[zje] AS '总金额', t1.[zds] AS '总吨数', t1.[lrsj] AS '创建时间', CONCAT ( MONTH ( t1.[rksj] ), '月' ) AS '入库时间', t1.[chpt] AS '撮合平台', t1.[qsfs] AS '签署方式', t1.[gfjc] AS '供方简称', t1.[cclx] AS '持仓类型', CAST ( t1.[htwj] AS VARCHAR ( MAX ) ) AS '合同文件', STUFF( ( SELECT ',' + CONVERT ( VARCHAR, CASE WHEN ISNUMERIC( REPLACE( t2.pp, ',', '' ) ) = 1 THEN CAST ( REPLACE( t2.pp, ',', '' ) AS FLOAT ) END ) FROM uf_cght2_dt1 t2 WHERE t1.id = t2.mainid FOR XML PATH ( '' ) ), 1, 1, '' ) AS '品牌', STUFF( ( SELECT ',' + CONVERT ( VARCHAR, CASE WHEN ISNUMERIC( REPLACE( t2.hsdj, ',', '' ) ) = 1 THEN CAST ( REPLACE( t2.hsdj, ',', '' ) AS FLOAT ) END ) FROM uf_cght2_dt1 t2 WHERE t1.id = t2.mainid FOR XML PATH ( '' ) ), 1, 1, '' ) AS '采购单价', SUM ( t3.[sjfk] ) AS '实际已付', SUM ( t3.[hkje] ) AS '已付货款', ( SELECT SUM ( sjfk ) FROM uf_cgfksjb WHERE kxlx = 0 AND cght = t1.id ) AS '订金', CASE WHEN (SELECT SUM(sjfk) FROM uf_cgfksjb WHERE kxlx = 0 AND cght = t1.id) + SUM(t3.[hkje]) < t1.[zje] THEN ROUND(SUM(t3.[hkje]) / t1.[zje], 3) ELSE ROUND(((SELECT SUM(sjfk) FROM uf_cgfksjb WHERE kxlx = 0 AND cght = t1.id) + SUM(t3.[hkje])) / t1.[zje],3) END AS '已付比例' FROM uf_cght2 t1 INNER JOIN uf_cght2_dt1 t2 ON t1.id = t2.mainid LEFT JOIN uf_cgfksjb t3 ON t1.id = t3.cght GROUP BY t1.id, t1.[gf], t1.[htmc], t1.[htbh], t1.[sjbh], t1.[qdrq], t1.[qsrq], t1.[jzrq], t1.[zje], t1.[zds], CONCAT ( MONTH ( t1.[rksj] ), '月' ), t1.[chpt], t1.[lrsj], t1.[qsfs], t1.[gfjc], t1.[cclx], CAST ( t1.[htwj] AS VARCHAR ( MAX ) );怎么按签定日期倒序排序

下的保密信息进行保密，并... WHEN ISNUMERIC(REPLACE(t2.pp, ',', '')) = 1 THEN。 9.3 本协议的附件与正文具有同等法律效力。请各方确认并签署本协议以示同意。甲方：_________________ 乙方：_________________

Error querying database. Cause: java.sql.SQLException: sql injection violation, deny schema : master : select taskTime,sum(allNum) 'taskNum',sum(doneNum) 'taskDoneNum' from ( select CONVERT(char(7),task_time,120) taskTime, count(*) allNum, COUNT(CASE WHEN current_status = '3' THEN 1 ELSE null END) doneNum from [grid_monitor].[dbo].[t_grid_task] where is_deleted = 0 and task_time >= dateadd(month, datediff(month, 0, dateAdd(month,-11,getdate())),0) and task_time < getdate() group by CONVERT(char(7),task_time,120) union select convert(varchar(7),DATEADD(month,number,dateadd(month, datediff(month, 0, dateAdd(month,-11,getdate())),0)),120) taskTime, 0 allNum,0 doneNum from MASTER..SPT_VALUES as a where a.type='P' and DATEADD(month,number,dateadd(month, datediff(month, 0, dateAdd(month,-11,getdate())),0)) < getdate() ) a group by taskTime order by taskTime

这个错误看起来像是SQL注入攻击，数据库检测到了非法字符或语句，并禁止了相关操作。如果您正在开发一个应用程序，可以尝试使用参数化查询来避免SQL注入攻击。如果这个查询是手动输入的，那么请确保您的查询语句没有...

select left(trans_date,7) as [month], country, count([state]) as trans_count, count(case [state] when 'approved' then 1 else null) as approved_count, sum(amount) as trans_total_amount, sum(case [state] when 'approved' then amount else 0) as approved_total_amount from Transactions group by country,[month] 报[42000] [Microsoft][ODBC Driver 17 for SQL Server][SQL Server]Incorrect syntax near ')'. (102) (SQLExecDirectW) 请修正

请将查询语句中的方括号（[]）替换为双引号（""），并在group by子句中... SUM(CASE [state] WHEN 'approved' THEN amount ELSE 0 END) AS approved_total_amount FROM Transactions GROUP BY country, "month";

select lot_id, max(claim_time)claim_time, count(case when(ope_category='Ship')then lot_id else null end) as LS, count(case when(ope_category='Unship') then lot_id else null end) as LUS from f3rpt.F3_TB_DAILY_FABOUT where substr(lot_id,1,2) not in('CA','CW','ES','E0','EM') and lot_type = 'Production' AND LOT_ID NOT LIKE 'H%' and substr(lot_id,7,4)='.00F' and ope_category in ('Ship','Unship') and year(claim_time) = year(current date - 1 days) and month(claim_time) = month(current date - 1 days) group by lot_id) as a where LS - LUS > 0 ，以上sql如何优化

SUM(CASE WHEN ope_category='Ship' THEN 1 ELSE 0 END) AS LS SUM(CASE WHEN ope_category='Unship' THEN 1 ELSE 0 END) AS LUS 3. 在WHERE子句中，使用了聚合函数，将查询结果限制在LS-LUS>0的记录，这种方式...

(select date(a.claim_time) as date, a.lot_id, a.lot_type,a.mainpd_id,a.prodspec_id,a.custprod_id, case when(date(b.created_time) <= '2009-01-05') then b.created_time + 21 days else b.created_time end as created_time, CASE WHEN A.CUST_id in ('MCA','NPA','SET') THEN a.COMPLETE_TIME ELSE a.COMPLETE_TIME END COMPLETE_TIME, a.cust_id as customer_id, a.ope_category, c.layer From f3rpt.F3_TB_DAILY_FABOUT a, f3rpt.fvlot b, (select mainpd_id, sum(masks)layer from f3rpt.ASMCRPT_VW_MAINPD_MASKS_ALL group by mainpd_id) as c, (select * from (select lot_id, max(claim_time)claim_time, count(case when(ope_category='Ship')then lot_id else null end) as LS, count(case when(ope_category='Unship') then lot_id else null end) as LUS from f3rpt.F3_TB_DAILY_FABOUT where substr(lot_id,1,2) not in('CA','CW','ES','E0','EM') and lot_type = 'Production' AND LOT_ID NOT LIKE 'H%' and substr(lot_id,7,4)='.00F' and ope_category in ('Ship','Unship') and year(claim_time) = year(current date - 1 days) and month(claim_time) = month(current date - 1 days) group by lot_id) as a where LS - LUS > 0 ) as lot Where a.lot_id = b.lot_id and b.mainpd_id = c.mainpd_id and a.lot_id = lot.LOT_ID and a.claim_time = lot.claim_time and a.ope_category = 'Ship' and a.cust_id in ('SM','BOE','GSC','NPA','GTA') ) as lot_hs 以上嵌套子查询，请拆分下

select lot_id, max(claim_time)claim_time, count(case when(ope_category='Ship')then lot_id else null end) as LS, count(case when(ope_category='Unship') then lot_id else null end) as LUS from f3rpt.F3_...

看下这段sql为何报错了 SELECT d.year,d.month,d.门店属性,sum(d.target_days) as target_days FROM (SELECT DISTINCT c.year,c.month,c.餐厅名称,c.门店编码,c.餐厅原始编号,c.品牌,c.门店属性,coalesce(c.target_days,0) as target_days FROM(SELECT year(a.日期) as year,month(a.日期) as month,a.*,case when a.品牌 like'大王早餐%' then b.operating_days else null end as target_days from input1 a left JOIN input2 b ON a.餐厅原始编号=b.storeid AND year(a.日期)=b.Year AND month(a.日期)=b.Month WHERE a.品牌 like'大王早餐%')c WHERE c.门店属性='KBF直营店')d GROUP BY 1,2,3 UNION SELECT input1.Year as year,input1.Month as month,input1.属性 as 门店属性,sum(input1.operating_days) as target_days from input1 GROUP BY 1,2,3 ORDER BY 3,1,2

SELECT year(a.日期) as year, month(a.日期) as month, a.*, case when a.品牌 like '大王早餐%' then b.operating_days else null end as target_days FROM input1 a LEFT JOIN input2 b ON a....

WITH t1 AS( -- t1表筛选出活动期间内的数据，并且为了防止一天有多次签到活动，distinct 去重 SELECT DISTINCT uid, DATE(in_time) dt, DENSE_RANK() over(PARTITION BY uid ORDER BY DATE(in_time)) rn -- 编号 FROM tb_user_log WHERE DATE(in_time) BETWEEN '2021-07-07' AND '2021-10-31' AND artical_id = 0 AND sign_in = 1 ), t2 AS ( SELECT *, DATE_SUB(dt,INTERVAL rn day) dt_tmp, case DENSE_RANK() over(PARTITION BY DATE_SUB(dt,INTERVAL rn day),uid ORDER BY dt )%7 -- 再次编号 WHEN 3 THEN 3 WHEN 0 THEN 7 ELSE 1 END as day_coin -- 用户当天签到时应该获得的金币数 FROM t1 ) SELECT uid,DATE_FORMAT(dt,'%Y%m') month, sum(day_coin) coin -- 总金币数 FROM t2 GROUP BY uid,DATE_FORMAT(dt,'%Y%m') ORDER BY DATE_FORMAT(dt,'%Y%m'),uid;

这段代码是一个SQL查询语句，用于计算用户在活动期间内的签到金币数。代码中使用了两个临时表t1和t2。 t1表根据条件筛选出活动期间内的数据，并使用DISTINCT关键字去重，得到每位用户在每天签到的第几次编号。这个...

WITH t1 AS( -- t1表筛选出活动期间内的数据，并且为了防止一天有多次签到活动，distinct 去重 SELECT DISTINCT uid, DATE(in_time) dt, DENSE_RANK() over(PARTITION BY uid ORDER BY DATE(in_time)) rn -- 编号 FROM tb_user_log WHERE DATE(in_time) BETWEEN '2021-07-07' AND '2021-10-31' AND artical_id = 0 AND sign_in = 1 ), t2 AS ( SELECT *, DATE_SUB(dt,INTERVAL rn day) dt_tmp, case DENSE_RANK() over(PARTITION BY DATE_SUB(dt,INTERVAL rn day),uid ORDER BY dt )%7 -- 再次编号 WHEN 3 THEN 3 WHEN 0 THEN 7 ELSE 1 END as day_coin -- 用户当天签到时应该获得的金币数 FROM t1 ) SELECT uid,DATE_FORMAT(dt,'%Y%m') month, sum(day_coin) coin -- 总金币数 FROM t2 GROUP BY uid,DATE_FORMAT(dt,'%Y%m') ORDER BY DATE_FORMAT(dt,'%Y%m'),uid;

这是一个使用MySQL语言编写的SQL查询语句，用于计算用户在活动期间内的签到金币数。以下是查询语句的解释： 1. 首先，使用子查询t1筛选出在活动期间内的签到数据，并通过DISTINCT关键字去除重复的签到记录。同时，...

select lot_hs.lot_id as lot_id,lot_type,lot_hs.mainpd_id, created_time,COMPLETE_TIME, value(bank.banktime,0) as banktime , round ( ( 1.00(days(COMPLETE_TIME)-days(created_time)) + (hour(COMPLETE_TIME)-hour(created_time))1.00/24 + (minute(COMPLETE_TIME)-minute(created_time))1.00/24/60 + (second(COMPLETE_TIME)-second(created_time))1.00/24/60/60) - value(bank.banktime,0),3) as use_days, customer_id, coalesce(cc.cust_id_define,lot_hs.customer_id) as cust_id2, cc.cycletime_target as ct_target, date,layer, round(count() over(partition by coalesce(cc.cust_id_define,lot_hs.customer_id),cc.cycletime_target)0.9,0) cnt, row_number() over(partition by coalesce(cc.cust_id_define,lot_hs.customer_id),cc.cycletime_target order by ( ( days(COMPLETE_TIME)-days(created_time) + (hour(COMPLETE_TIME)-hour(created_time))1.00/24 + (minute(COMPLETE_TIME)-minute(created_time))1.00/24/60 + (second(COMPLETE_TIME)-second(created_time))1.00/24/60/60) - value(bank.banktime,0))/layer) id From (select date(a.claim_time) as date, a.lot_id, a.lot_type,a.mainpd_id,a.prodspec_id,a.custprod_id, case when(date(b.created_time) <= '2009-01-05') then b.created_time + 21 days else b.created_time end as created_time, CASE WHEN A.CUST_id in ('MCA','NPA','SET') THEN a.COMPLETE_TIME ELSE a.COMPLETE_TIME END COMPLETE_TIME, a.cust_id as customer_id, a.ope_category, c.layer From f3rpt.F3_TB_DAILY_FABOUT a, f3rpt.fvlot b, (select mainpd_id, sum(masks)layer from f3rpt.ASMCRPT_VW_MAINPD_MASKS_ALL group by mainpd_id) as c, (select from (select lot_id, max(claim_time)claim_time, count(case when(ope_category='Ship')then lot_id else null end) as LS, count(case when(ope_category='Unship') then lot_id else null end) as LUS from f3rpt.F3_TB_DAILY_FABOUT where substr(lot_id,1,2) not in('CA','CW','ES','E0','EM') and lot_type = 'Production' AND LOT_ID NOT LIKE 'H%' and substr(lot_id,7,4)='.00F' and ope_category in ('Ship','Unship') and year(claim_time) = year(current date - 1 days) and month(claim_time) = month(current date - 1 days) group by lot_id) as a where LS - LUS > 0 ) as lot Where a.lot_id = b.lot_id and b.mainpd_id = c.mainpd_id and a.lot_id = lot.LOT_ID and a.claim_time = lot.claim_time and a.ope_category = 'Ship' and a.cust_id in ('SM','BOE','GSC','NPA','GTA') ) as lot_hs left outer join (select lot_id,max(bankin_time) banktime from f3rpt.asmc_dpm where bankin_time>0 group by lot_id) bank on (lot_hs.lot_id = bank.lot_id) left join f3cim.f3cim_cfg_cust_rule cc on case when lot_hs.customer_id='WXM' THEN 'WII'||SUBSTR(lot_hs.mainpd_id,6,1) else lot_hs.customer_id end = cc.cust_id and locate(cc.mainpd_id,lot_hs.mainpd_id)>0 and locate(cc.prodspec_id,lot_hs.prodspec_id)>0 and locate(cc.custprod_id_45,substr(lot_hs.custprod_id,3,3))>0 where lot_hs.ope_category = 'Ship' ；以上sql如何优化

这是一个比较复杂的 SQL 语句，可以从以下几个方面考虑进行优化： 1.使用 JOIN 替代子查询可以使用 JOIN 语句替代子查询，可以提高查询效率。例如，将以下子查询： (select mainpd_id, sum(masks)layer from...

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