java实现井字棋游戏
时间: 2023-07-11 12:08:25 浏览: 51
以下是一个简单的 Java 代码实现井字棋游戏:
```
import java.util.Scanner;
public class TicTacToe {
private char[][] board; // 二维数组表示棋盘
private char currentPlayer; // 当前玩家
public TicTacToe() {
board = new char[3][3];
currentPlayer = 'X';
initializeBoard();
}
// 初始化棋盘
public void initializeBoard() {
for (int i = 0; i < 3; i++) {
for (int j = 0; j < 3; j++) {
board[i][j] = '-';
}
}
}
// 打印棋盘
public void printBoard() {
System.out.println("-------------");
for (int i = 0; i < 3; i++) {
System.out.print("| ");
for (int j = 0; j < 3; j++) {
System.out.print(board[i][j] + " | ");
}
System.out.println();
System.out.println("-------------");
}
}
// 判断棋盘是否已满
public boolean isBoardFull() {
boolean isFull = true;
for (int i = 0; i < 3; i++) {
for (int j = 0; j < 3; j++) {
if (board[i][j] == '-') {
isFull = false;
}
}
}
return isFull;
}
// 判断是否有玩家胜利
public boolean checkForWin() {
boolean rowWin = checkRowsForWin();
boolean columnWin = checkColumnsForWin();
boolean diagonalWin = checkDiagonalsForWin();
return rowWin || columnWin || diagonalWin;
}
// 检查行是否有玩家胜利
private boolean checkRowsForWin() {
for (int i = 0; i < 3; i++) {
if (checkRowCol(board[i][0], board[i][1], board[i][2])) {
return true;
}
}
return false;
}
// 检查列是否有玩家胜利
private boolean checkColumnsForWin() {
for (int i = 0; i < 3; i++) {
if (checkRowCol(board[0][i], board[1][i], board[2][i])) {
return true;
}
}
return false;
}
// 检查对角线是否有玩家胜利
private boolean checkDiagonalsForWin() {
return checkRowCol(board[0][0], board[1][1], board[2][2])
|| checkRowCol(board[0][2], board[1][1], board[2][0]);
}
// 检查一行或一列是否都是同一个玩家的棋子
private boolean checkRowCol(char c1, char c2, char c3) {
return c1 != '-' && c1 == c2 && c2 == c3;
}
// 切换玩家
public void changePlayer() {
if (currentPlayer == 'X') {
currentPlayer = 'O';
} else {
currentPlayer = 'X';
}
}
// 玩家下棋
public void play() {
Scanner scanner = new Scanner(System.in);
while (!isBoardFull() && !checkForWin()) {
System.out.println(currentPlayer + " 的回合,请输入行和列(1-3):");
int row = scanner.nextInt() - 1;
int col = scanner.nextInt() - 1;
if (row >= 0 && row < 3 && col >= 0 && col < 3 && board[row][col] == '-') {
board[row][col] = currentPlayer;
changePlayer();
printBoard();
} else {
System.out.println("无效的位置,请重新输入!");
}
}
if (checkForWin()) {
System.out.println("恭喜 " + currentPlayer + " 获胜!");
} else {
System.out.println("平局!");
}
scanner.close();
}
public static void main(String[] args) {
TicTacToe game = new TicTacToe();
game.printBoard();
game.play();
}
}
```
以上代码只是一个简单的实现,可以根据需要进行修改和优化。