基于c++的卡诺图化简程序

以下是一份C语言的卡诺图化简程序的示例代码：

#include <stdio.h>
#include <stdlib.h>

#define N 4 // 定义变量的位数
#define M 16 // 定义卡诺图的行数

int bin[M][N]; // M行N列的二进制矩阵
int kmap[M]; // 卡诺图的值
int ans[M]; // 化简后的值

void print() {
int i, j;

printf("K-map:\n");

for (i = 0; i < M; i++) {
for (j = 0; j < N; j++)
printf("%d ", bin[i][j]);
printf("%d\n", kmap[i]);
}

printf("\n");

printf("Simplified expression: ");

for (i = 0; i < M; i++) {
if (ans[i] == 1) {
for (j = 0; j < N; j++) {
if (bin[i][j]) printf("A%d'", j + 1);
else printf("A%d", j + 1);
}

printf(" + ");
}
}

printf("\n");
}

void simplify() {
int cur = 0, i, j;
int group[4][M], gc[4];
int idx[M], u[M];

for (i = 0; i < M; i++) u[i] = -1;

for (i = 0; i < N - 1; i++) {
// 将相邻的1分为一组，相邻的0分为一组
gc[0] = gc[1] = gc[2] = gc[3] = 0;

for (j = 0; j < M; j++) {
int t = bin[j][i] + bin[j][i + 1] * 2;

if (kmap[j] == 1) group[t][gc[t]++] = j;
}

// 把每组的值设为 cur
for (j = 0; j < gc[1]; j++) idx[group[1][j]] = cur;
for (j = 0; j < gc[2]; j++) idx[group[2][j]] = cur;
cur++; // 下一组的值为 cur+1

for (j = 0; j < gc[0]; j++) idx[group[0][j]] = -1;
for (j = 0; j < gc[3]; j++) idx[group[3][j]] = -1;
}

// 这部分与上面的基本相同，不过要考虑第一位和第四位是否可连接
gc[0] = gc[1] = gc[2] = gc[3] = 0;

for (i = 0; i < M; i++) {
if (bin[i][0] == 1 && bin[i][N - 1] == 1) {
idx[i] = cur;
continue;
}

int t = bin[i][N - 1] + bin[i][0] * 2;

if (kmap[i] == 1) group[t][gc[t]++] = i;
}

for (j = 0; j < gc[1]; j++) idx[group[1][j]] = cur;
for (j = 0; j < gc[2]; j++) idx[group[2][j]] = cur;
cur++;

for (j = 0; j < gc[0]; j++) idx[group[0][j]] = -1;
for (j = 0; j < gc[3]; j++) idx[group[3][j]] = -1;

// 把每组输出
for (i = 0; i < cur; i++) {
int cnt = 0;
for (j = 0; j < M; j++) {
if (idx[j] == i) {
ans[j] = 1;
cnt++;
}
else ans[j] = 0;
}
}
}

int main() {
int i, j, t;

for (i = 0; i < M; i++) {
t = i;
for (j = N - 1; j >= 0; j--) {
bin[i][j] = t % 2;
t /= 2;
}

printf("Enter the value for ");
for (j = 0; j < N; j++)
printf("A%d ", j + 1);
printf(": ");

scanf("%d", &kmap[i]);
}

printf("\n");

simplify();
print();

return 0;
}