将十进制转化为二进制用C++实现

在C++中将十进制转换为二进制可以使用内置库函数`bitset`，或者手动通过循环除以2并取余数的方式来实现。这里我会展示两种方法：

1. **使用bitset**:

#include <bitset>
#include <iostream>

std::string decimalToBinary(int decimal) {
    std::bitset<32> binary(decimal); // 使用32位bitset来存储，实际需要根据decimal的最大值调整
    return binary.to_string();
}

int main() {
    int number = 42;
    std::cout << "Binary representation of " << number << " is: " << decimalToBinary(number) << std::endl;
    return 0;
}

2. **手动计算** (Long Division Algorithm):

#include <iostream>
#include <string>

std::string decimalToBinaryManually(int decimal) {
    std::string binary = "";
    while (decimal > 0) {
        binary = std::to_string(decimal % 2) + binary;
        decimal /= 2;
    }
    return binary;
}

int main() {
    int number = 42;
    std::cout << "Binary representation of " << number << " is: " << decimalToBinaryManually(number) << std::endl;
    return 0;
}