用Java写一个实现平面求最短距离的两个点的代码，并且提现分治思想

好的，以下是一个用Java实现平面求最短距离的两个点的代码，同时也体现了分治思想：

import java.util.*;

public class ClosestPair {

    static class Point {
        double x, y;

        public Point(double x, double y) {
            this.x = x;
            this.y = y;
        }
    }

    static class Pair {
        Point p1, p2;
        double distance;

        public Pair(Point p1, Point p2, double distance) {
            this.p1 = p1;
            this.p2 = p2;
            this.distance = distance;
        }
    }

    public static Pair closestPair(Point[] points) {
        Arrays.sort(points, (p1, p2) -> Double.compare(p1.x, p2.x));
        return closestPair(points, 0, points.length - 1);
    }

    private static Pair closestPair(Point[] points, int left, int right) {
        if (left >= right) {
            return null;
        }
        int mid = (left + right) / 2;
        Pair leftPair = closestPair(points, left, mid);
        Pair rightPair = closestPair(points, mid + 1, right);
        Pair minPair = min(leftPair, rightPair);
        List<Point> strip = new ArrayList<>();
        double midX = points[mid].x;
        for (int i = left; i <= right; i++) {
            if (Math.abs(points[i].x - midX) < minPair.distance) {
                strip.add(points[i]);
            }
        }
        strip.sort((p1, p2) -> Double.compare(p1.y, p2.y));
        for (int i = 0; i < strip.size(); i++) {
            for (int j = i + 1; j < strip.size() && strip.get(j).y - strip.get(i).y < minPair.distance; j++) {
                Pair pair = new Pair(strip.get(i), strip.get(j), distance(strip.get(i), strip.get(j)));
                if (pair.distance < minPair.distance) {
                    minPair = pair;
                }
            }
        }
        return minPair;
    }

    private static Pair min(Pair p1, Pair p2) {
        if (p1 == null) {
            return p2;
        }
        if (p2 == null) {
            return p1;
        }
        return p1.distance < p2.distance ? p1 : p2;
    }

    private static double distance(Point p1, Point p2) {
        double dx = p1.x - p2.x;
        double dy = p1.y - p2.y;
        return Math.sqrt(dx * dx + dy * dy);
    }

    public static void main(String[] args) {
        Point[] points = new Point[] { new Point(0, 0), new Point(1, 1), new Point(2, 2), new Point(3, 3) };
        Pair pair = closestPair(points);
        System.out.println(pair.distance);
    }
}

这个算法的思想是：先按照x坐标排序，然后递归地将点集分成左右两部分，分别求出左右两部分的最近点对，然后取两部分中最近的点对作为当前区间的最近点对。接着，我们需要考虑两个点分别在左右两部分的情况，这时我们需要将点集按照y坐标排序，然后在中间的一段区间内暴力枚举所有点对，找到距离最近的点对。最后，我们将三种情况中距离最近的点对作为整个点集的最近点对。

希望这个代码能够帮到你！