python数独游戏源代码100行

Python数独游戏源代码100行是一段基于Python语言编写的程序，实现了以数学题目为主题的益智游戏，玩家需要根据规则在九宫格内填入数字，使得每行、每列和每个3x3格子里的数字均为1-9且不重复。

这个程序总共包含100行，其中包括导入模块、定义变量和函数、循环和条件语句、以及基本的输出和输入功能。在程序开头，首先会定义一个9x9的空矩阵，作为数独的游戏板。

程序中还包括很多实用的方法和函数，比如判断是否填满、验证数字是否符合规则、随机填入数字等。此外，程序还针对不同级别的游戏难度做了不同的设置，比如对空白格子数量的限制、填入数字时的提示等。

该程序同时也几乎实现了所有数独游戏规则，不仅可以求解数独游戏，还提供了用户自主输入数独题目和随机生成数独题目的功能。

总之，Python数独游戏源代码100行极大地提升了我们尝试解决数独游戏难题的乐趣，并为我们提供了一个好的平台，可以不断地挑战自己，以及向其他用户展示我们的成果和分数排名。

相关问题

python数独游戏源代码

以下是一个简单的Python数独游戏源代码：

import random

# 创建数独棋盘
def create_board():
    seed = [1, 2, 3, 4, 5, 6, 7, 8, 9]
    random.shuffle(seed)
    board = [[0]*9 for i in range(9)]
    for i in range(9):
        board[0][i] = seed[i]
    for i in range(1, 9):
        for j in range(9):
            board[i][j] = board[i-1][(j+3)%9]
    return board

# 打印数独棋盘
def print_board(board):
    print("-"*25)
    for i in range(9):
        for j in range(9):
            print(board[i][j], end=" ")
            if j%3 == 2:
                print("|", end=" ")
        print()
        if i%3 == 2:
            print("-"*25)

# 检查行、列、小九宫格是否有重复数字
def check(board, row, col, num):
    for i in range(9):
        if board[row][i] == num:
            return False
    for i in range(9):
        if board[i][col] == num:
            return False
    r = (row//3)*3
    c = (col//3)*3
    for i in range(3):
        for j in range(3):
            if board[r+i][c+j] == num:
                return False
    return True

# 解数独
def solve(board):
    for row in range(9):
        for col in range(9):
            if board[row][col] == 0:
                for num in range(1, 10):
                    if check(board, row, col, num):
                        board[row][col] = num
                        if solve(board):
                            return True
                        board[row][col] = 0
                return False
    return True

# 创建数独棋盘并解决
board = create_board()
print("原始数独：")
print_board(board)
solve(board)
print("解决后的数独：")
print_board(board)

可以通过调用`create_board()`函数创建一个数独棋盘，通过调用`solve()`函数解决数独，最后通过调用`print_board()`函数打印结果。

Python制作数独游戏源代码

以下是一个简单的 Python 制作数独游戏的源代码，使用 Pygame 库实现游戏界面：

import pygame
import numpy as np
import time

pygame.init()

# 游戏窗口尺寸
WINDOW_SIZE = (540, 600)

# 游戏窗口标题
pygame.display.set_caption("数独游戏")

# 游戏窗口
screen = pygame.display.set_mode(WINDOW_SIZE)

# 数独棋盘
board = np.array([[7, 8, 0, 4, 0, 0, 1, 2, 0],
                  [6, 0, 0, 0, 7, 5, 0, 0, 9],
                  [0, 0, 0, 6, 0, 1, 0, 7, 8],
                  [0, 0, 7, 0, 4, 0, 2, 6, 0],
                  [0, 0, 1, 0, 5, 0, 9, 3, 0],
                  [9, 0, 4, 0, 6, 0, 0, 0, 5],
                  [0, 7, 0, 3, 0, 0, 0, 1, 2],
                  [1, 2, 0, 0, 0, 7, 4, 0, 0],
                  [0, 4, 9, 2, 0, 6, 0, 0, 7]])

# 数独棋盘位置
BOARD_POS = (20, 80)

# 数字方格尺寸
CELL_SIZE = 50

# 数字方格颜色
CELL_COLOR = (255, 255, 255)

# 数字方格线宽
CELL_LINE_WIDTH = 1

# 数字字体
FONT = pygame.font.SysFont('Arial', 36)

# 游戏是否结束
game_over = False

# 绘制数独棋盘
def draw_board():
    for i in range(9):
        for j in range(9):
            pygame.draw.rect(screen, CELL_COLOR, (BOARD_POS[0] + j*CELL_SIZE, BOARD_POS[1] + i*CELL_SIZE, CELL_SIZE, CELL_SIZE), 0)
            pygame.draw.rect(screen, (0, 0, 0), (BOARD_POS[0] + j*CELL_SIZE, BOARD_POS[1] + i*CELL_SIZE, CELL_SIZE, CELL_SIZE), CELL_LINE_WIDTH)
            if board[i][j] != 0:
                text = FONT.render(str(board[i][j]), True, (0, 0, 0))
                text_rect = text.get_rect()
                text_rect.center = (BOARD_POS[0] + (j+0.5)*CELL_SIZE, BOARD_POS[1] + (i+0.5)*CELL_SIZE)
                screen.blit(text, text_rect)

# 检查数独是否解决
def check_win():
    for i in range(9):
        for j in range(9):
            if board[i][j] == 0:
                return False
    return True

# 显示游戏结束画面
def show_game_over():
    text = FONT.render("游戏结束", True, (0, 0, 0))
    text_rect = text.get_rect()
    text_rect.center = (WINDOW_SIZE[0] / 2, WINDOW_SIZE[1] / 2 - 50)
    screen.blit(text, text_rect)

    text2 = FONT.render("按 R 重新开始", True, (0, 0, 0))
    text2_rect = text2.get_rect()
    text2_rect.center = (WINDOW_SIZE[0] / 2, WINDOW_SIZE[1] / 2 + 50)
    screen.blit(text2, text2_rect)

# 重置游戏
def reset_game():
    global board, game_over
    board = np.array([[7, 8, 0, 4, 0, 0, 1, 2, 0],
                      [6, 0, 0, 0, 7, 5, 0, 0, 9],
                      [0, 0, 0, 6, 0, 1, 0, 7, 8],
                      [0, 0, 7, 0, 4, 0, 2, 6, 0],
                      [0, 0, 1, 0, 5, 0, 9, 3, 0],
                      [9, 0, 4, 0, 6, 0, 0, 0, 5],
                      [0, 7, 0, 3, 0, 0, 0, 1, 2],
                      [1, 2, 0, 0, 0, 7, 4, 0, 0],
                      [0, 4, 9, 2, 0, 6, 0, 0, 7]])
    game_over = False

# 游戏循环
while True:
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            pygame.quit()
            quit()
        if event.type == pygame.KEYDOWN:
            if event.key == pygame.K_r and game_over:
                reset_game()
        if event.type == pygame.MOUSEBUTTONDOWN and not game_over:
            pos = pygame.mouse.get_pos()
            if pos[0] >= BOARD_POS[0] and pos[1] >= BOARD_POS[1] and pos[0] < BOARD_POS[0] + 9*CELL_SIZE and pos[1] < BOARD_POS[1] + 9*CELL_SIZE:
                row = (pos[1] - BOARD_POS[1]) // CELL_SIZE
                col = (pos[0] - BOARD_POS[0]) // CELL_SIZE
                if board[row][col] == 0:
                    for i in range(1, 10):
                        if np.count_nonzero(board[row] == i) == 0 and np.count_nonzero(board[:, col] == i) == 0:
                            box_x = col // 3
                            box_y = row // 3
                            if np.count_nonzero(board[box_y*3:box_y*3+3, box_x*3:box_x*3+3] == i) == 0:
                                board[row][col] = i
                                if check_win():
                                    game_over = True

    screen.fill((255, 255, 255))
    draw_board()
    if game_over:
        show_game_over()
    pygame.display.update()

运行结果：