将下面一段matlab代码转换为python代码（function point_bridge1 = zuobiao_qiao(global_coords,juli_qiaoche) %UNTITLED5 用于将桥梁绝对坐标转换为相对坐标 % 此处显示详细说明 local_coords(:,1) = global_coords(:,1) - global_coords(1,1); local_coords(:,2) = global_coords(:,2) - global_coords(1,2); % 计算1点和4点的连线向量 v = local_coords(2,:) - local_coords(1,:); % 计算旋转角度 theta = -atan2(v(2), v(1)); R = [cos(theta) -sin(theta); sin(theta) cos(theta)]; rotated_point = local_coords(:,:) * R; point_bridge1(:,1) = rotated_point (:,1) point_bridge1(1,2) = rotated_point(1,2)-juli_qiaoche(1); point_bridge1(2,2) = rotated_point(2,2)+juli_qiaoche(2); point_bridge1(3,2) = rotated_point(3,2)+juli_qiaoche(3); point_bridge1(4,2) = rotated_point(4,2)-juli_qiaoche(4); point_bridge1(:,2) = point_bridge1(:,2) - point_bridge1(1,2); end）

以下是将 MATLAB 代码转换为 Python 代码后的结果：

import numpy as np

def zuobiao_qiao(global_coords, juli_qiaoche):
    local_coords = np.zeros_like(global_coords)
    local_coords[:, 0] = global_coords[:, 0] - global_coords[0, 0]
    local_coords[:, 1] = global_coords[:, 1] - global_coords[0, 1]
    v = local_coords[1, :] - local_coords[0, :]
    theta = -np.arctan2(v[1], v[0])
    R = np.array([[np.cos(theta), -np.sin(theta)], [np.sin(theta), np.cos(theta)]])
    rotated_point = np.dot(local_coords, R)
    point_bridge1 = np.zeros((4, 2))
    point_bridge1[:, 0] = rotated_point[:, 0]
    point_bridge1[0, 1] = rotated_point[0, 1] - juli_qiaoche[0]
    point_bridge1[1, 1] = rotated_point[1, 1] + juli_qiaoche[1]
    point_bridge1[2, 1] = rotated_point[2, 1] + juli_qiaoche[2]
    point_bridge1[3, 1] = rotated_point[3, 1] - juli_qiaoche[3]
    point_bridge1[:, 1] = point_bridge1[:, 1] - point_bridge1[0, 1]
    return point_bridge1

请注意，这里使用的是 NumPy 库中的矩阵运算，因此需要将输入的数组转换为 NumPy 数组。此外，由于 Python 中的索引从 0 开始，因此在 Python 代码中需要将索引减去 1。