请写python程序实现实数的“三位一并法”与“四位一并法”。输入一个8进制小数,输出有两个,首先用“三位一并法”将输入的八进制数转换为二进制实数,并且输出。然后用“四位一并法”将得到的二进制实数转换为16进制数,并且输出。
时间: 2024-12-17 08:24:40 浏览: 5
当然,这里有一个简单的Python程序,它实现了从八进制到二进制的"三位一并"转换以及从二进制到十六进制的"四位一并"转换:
```python
def octal_to_3_digit_binary(octal_num):
decimal_num = int(octal_num, 8)
binary_num = format(decimal_num, '032b') # 生成完整的32位二进制字符串
return [group for i, group in enumerate(binary_num, start=1) if i % 3 == 0]
def binary_to_4_digit_hex(binary_group):
hex_num = hex(int(binary_group, 2))[2:].upper() # 转换为16进制,去掉前缀'0x'
return '0x' + (''.join(hex_num[i:i+4] for i in range(0, len(hex_num), 4))) # 四位一并
def main():
octal_input = input("请输入一个8进制小数:")
three_digit_binary = octal_to_3_digit_binary(octal_input)
print("三位一并的二进制是:", three_digit_binary)
four_digit_hexes = [binary_to_4_digit_hex(group) for group in three_digit_binary]
print("四位一并的十六进制是:", four_digit_hexes)
if __name__ == "__main__":
main()
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