编写一个shell脚本，接受一个目录作为参数，递归遍历该目录下的所有文件以及子文件夹，统计输出.log文件与.txt文件数量、及相关文件路径

Sure! Here's a shell script that accepts a directory as a parameter, recursively traverses all files and subdirectories within that directory, and outputs the count of `.log` and `.txt` files along with their respective file paths:

#!/bin/bash

# Function to recursively traverse directory
traverse_directory() {
    local dir=$1
    
    # Loop through each file and subdirectory in the given directory
    for file in "$dir"/*; do
        if [ -f "$file" ]; then
            # Check if the file has .log or .txt extension
            if [[ $file == *.log ]]; then
                echo "Log file found: $file"
                ((log_count++))
            elif [[ $file == *.txt ]]; then
                echo "Text file found: $file"
                ((txt_count++))
            fi
        elif [ -d "$file" ]; then
            # Recursively call the function for subdirectories
            traverse_directory "$file"
        fi
    done
}

# Check if directory is provided as argument
if [ $# -eq 0 ]; then
    echo "Please provide a directory as an argument."
    exit 1
fi

# Initialize file count variables
log_count=0
txt_count=0

# Call the function to traverse the directory
traverse_directory "$1"

# Output the file counts
echo "Number of log files: $log_count"
echo "Number of text files: $txt_count"

To use this script, save it to a file (e.g., `file_count.sh`), make it executable using `chmod +x file_count.sh`, and then run it with the desired directory as the argument:

./file_count.sh /path/to/directory

Replace `/path/to/directory` with the actual directory path you want to traverse. The script will recursively search for `.log` and `.txt` files and print their counts along with the file paths.