if [[ $(chage -l $user | grep "Password expires" | cut -d: -f2 | tr -d ' ') == "never" ]] then echo "$user: Password never expires"这段代码加一个等于“从不”的条件

可以这样修改：

if [[ $(chage -l $user | grep "Password expires" | cut -d: -f2 | tr -d ' ') == "never" || $(chage -l $user | grep "Password expires" | cut -d: -f2 | tr -d ' ') == "从不" ]]
then
    echo "$user: Password never expires"
fi

这样就可以同时判断密码过期时间是否等于“never”或“从不”。

相关问题

#!/bin/bash users=$(cut -d: -f1 /etc/passwd) for user in $users do if [[ $(getent passwd $user | cut -d: -f3) -ge 1000 ]] then if [[ $(chage -l $user | grep "Password expires" | grep "密码过期时间" | cut -d: -f2 | tr -d ' ') == "never" || $(chage -l $user | grep "Password expires" | grep "密码过期时间" | cut -d: -f2 | tr -d ' ') == "从不" ]] then echo "$user: Password never expires" else expire_date=$(date -d "$(chage -l $user | grep "Password expires" | cut -d: -f2 | tr -d ' ')" +%s) current_date=$(date +%s) if [[ $expire_date -lt $current_date ]] then echo "$(hostname -I | awk '{print $1}'), $user: Password has expired" else echo "$user: Password will expire on $(chage -l $user | grep "Password expires" | cut -d: -f2 | tr -d ' ')" fi fi else account_status=$(passwd -S $user | awk '{print $2}') if [[ "$account_status" == "L" ]]; then echo "$(hostname -I | awk '{print $1}'), User $user: account locked!" fi fi done这段代码去掉筛选非系统用户

可以将第4行改为：

users=$(cut -d: -f1 /etc/passwd | grep -v -E "nologin|false|sync|shutdown|halt")

这样就会排除掉系统用户了。

#!/bin/bash users=$(cut -d: -f1 /etc/passwd) for user in $users do if [[ $(getent passwd $user | cut -d: -f3) -ge 1000 ]] then if [[ $(chage -l $user | grep "Password expires" | cut -d: -f2 | tr -d ' ') == "never" ]] then echo "$user: Password never expires" else expire_date=$(date -d "$(chage -l $user | grep "Password expires" | cut -d: -f2 | tr -d ' ')" +%s) current_date=$(date +%s) if [[ $expire_date -lt $current_date ]] then echo "$(hostname -I | awk '{print $1}'),$user: Password has expired" else echo "$user: Password will expire on $(chage -l $user | grep "Password expires" | cut -d: -f2 | tr -d ' ')" fi fi else echo "" account_status=$(passwd -S $user | awk '{print $2}') if [[ "$account_status" == "L" ]]; then echo "$(hostname -I | awk '{print $1}'),User $user: account locked!" fi done语法问题

在第27行缺少一个 `fi` 关键字来结束第20行的 `if` 语句。同时，第24行的 `echo` 命令中，应该把逗号放在双引号内，否则会被视为两个参数。正确的脚本如下：

#!/bin/bash

users=$(cut -d: -f1 /etc/passwd)

for user in $users
do
    if [[ $(getent passwd $user | cut -d: -f3) -ge 1000 ]]
    then
        if [[ $(chage -l $user | grep "Password expires" | cut -d: -f2 | tr -d ' ') == "never" ]]
        then
            echo "$user: Password never expires"
        else
            expire_date=$(date -d "$(chage -l $user | grep "Password expires" | cut -d: -f2 | tr -d ' ')" +%s)
            current_date=$(date +%s)
            if [[ $expire_date -lt $current_date ]]
            then
                echo "$(hostname -I | awk '{print $1}'), $user: Password has expired"
            else
                echo "$user: Password will expire on $(chage -l $user | grep "Password expires" | cut -d: -f2 | tr -d ' ')"
            fi
        fi
    else
        account_status=$(passwd -S $user | awk '{print $2}')
        if [[ "$account_status" == "L" ]]; then
            echo "$(hostname -I | awk '{print $1}'), User $user: account locked!"
        fi
    fi
done