用c语言求s=1!+2!+...+n!

以下是用C语言求s=1!+2!+...+n!的代码实现：

#include <stdio.h>
int main(void) {
    int n = 0;
    int i = 0;
    int m = 1;
    int sum=0;
    printf("请输入n的值:");    scanf("%d", &n);
    for (i=1; i<=n; ++i) {
        m = m * i;
        sum = sum +m;
    }
    printf ("sum = %d\n", sum);
    return 0;
}