使用C语言完成下列题目(1)模拟实现下面磁盘调度算法中的任意一个:最短寻道时间优先算法。扫描算法。 (2)要求计算磁盘调度算法的平均寻道长度。 (3)要求能够编写磁盘调度算法函数。同时说明实验中出现的问题和解决方法
时间: 2024-02-24 21:55:47 浏览: 68
下面是使用C语言完成磁盘调度算法的代码实现,其中包括最短寻道时间优先算法和扫描算法,并计算平均寻道长度:
```c
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
// 最大磁道数
#define MAX_TRACKS 200
// 最大请求数
#define MAX_REQUESTS 1000
// 存储请求的结构体
typedef struct {
int track; // 磁道号
int visited; // 是否访问过
} Request;
// 磁盘调度算法函数定义
typedef void (*DiskSchedulingAlgorithm)(Request* requests, int num_requests, int start_track, int* sequence, int* total_seek);
// 实现最短寻道时间优先算法
void shortestSeekTimeFirst(Request* requests, int num_requests, int start_track, int* sequence, int* total_seek) {
int current_track = start_track;
int num_visited = 0;
while (num_visited < num_requests) {
int next_track = -1;
int min_seek = MAX_TRACKS;
for (int i = 0; i < num_requests; i++) {
if (!requests[i].visited) {
int seek = abs(requests[i].track - current_track);
if (seek < min_seek) {
min_seek = seek;
next_track = requests[i].track;
}
}
}
if (next_track >= 0) {
sequence[num_visited] = next_track;
*total_seek += min_seek;
current_track = next_track;
num_visited++;
requests[next_track].visited = 1;
}
}
}
// 实现扫描算法
void scan(Request* requests, int num_requests, int start_track, int* sequence, int* total_seek) {
int current_track = start_track;
int num_visited = 0;
int direction = 1; // 扫描方向,1表示向外,-1表示向内
while (num_visited < num_requests) {
int next_track = -1;
int min_seek = MAX_TRACKS;
for (int i = 0; i < num_requests; i++) {
if (!requests[i].visited) {
int seek = abs(requests[i].track - current_track);
if (seek < min_seek && (current_track <= requests[i].track && direction == 1 || current_track >= requests[i].track && direction == -1)) {
min_seek = seek;
next_track = requests[i].track;
}
}
}
if (next_track >= 0) {
sequence[num_visited] = next_track;
*total_seek += min_seek;
current_track = next_track;
num_visited++;
requests[next_track].visited = 1;
} else {
direction = -direction;
}
}
}
// 计算平均寻道长度
float calculateAverageSeekLength(int* sequence, int num_requests, int start_track) {
int total_seek = 0;
for (int i = 0; i < num_requests; i++) {
total_seek += abs(sequence[i] - start_track);
start_track = sequence[i];
}
return (float)total_seek / num_requests;
}
int main() {
// 读取输入
int num_requests, start_track;
DiskSchedulingAlgorithm algorithm;
printf("请输入请求总数:");
scanf("%d", &num_requests);
Request* requests = (Request*)malloc(num_requests * sizeof(Request));
for (int i = 0; i < num_requests; i++) {
printf("请输入第%d个请求的磁道号:", i + 1);
scanf("%d", &requests[i].track);
requests[i].visited = 0;
}
printf("请输入起始磁道号:");
scanf("%d", &start_track);
printf("请选择磁盘调度算法(1-最短寻道时间优先,2-扫描):");
int choice;
scanf("%d", &choice);
if (choice == 1) {
algorithm = shortestSeekTimeFirst;
} else if (choice == 2) {
algorithm = scan;
} else {
printf("输入有误!\n");
return 1;
}
// 调用磁盘调度算法函数
int* sequence = (int*)malloc(num_requests * sizeof(int));
int total_seek = 0;
algorithm(requests, num_requests, start_track, sequence, &total_seek);
// 输出结果
printf("磁道访问顺序:");
for (int i = 0; i < num_requests; i++) {
printf("%d ", sequence[i]);
}
printf("\n平均寻道长度:%.2f\n", calculateAverageSeekLength(sequence, num_requests, start_track));
// 释放内存
free(requests);
free(sequence);
return 0;
}
```
在实验中可能会出现一些问题,例如:
1. 请求的数量和磁道号范围过大,程序运行时间过长。可以通过增加程序的效率、增加计算机的性能等方式来解决。
2. 输入的数据格式不正确,可能导致程序出现错误。可以增加输入数据的验证,确保输入的数据格式正确。
3. 磁盘调度算法的结果不同,可能导致平均寻道长度的计算结果不同。可以通过对多个算法的结果进行对比,选择最优的算法。
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