用matlab写一个解(m*m*g/(k*k))*log(1-(k*x)/(m*(v0-v)))+(m*g/k)*(x/(v0))-300==0的程序

可以使用MATLAB内置的函数fzero来求解这个方程。代码如下：

g = 9.81;   % 重力加速度
m = 68.1;   % 物体质量
v0 = 40;    % 初始速度
k = 12.5;   % 阻力系数

f = @(x) (m*g/k)*(x/(v0)) + (m*m*g/(k*k))*log(1-(k*x)/(m*(v0-x))) - 300;

x0 = 0;     % 初始猜测值
x = fzero(f, x0);   % 求解方程

disp(['x = ' num2str(x)]);

这段代码中，我们首先定义了一些常数，然后定义了一个匿名函数f，该函数表示方程的左边减去右边的值。然后，我们使用fzero函数求解方程，其中x0是初始猜测值。最后，我们输出解x的值。

注意，由于log函数的定义域是(0, +∞)，因此x的值必须小于v0才能满足方程的要求。

相关问题

将u = M*x; q = sqrt(x’*u); x = x/q; u = u/q; v = A*x; rho = x’*v; k = 0; g = x; gnorm = 1; log=[]; % Initialisierungen while gnorm > tol, k = k + 1; galt = g; if exist(’C’), g = 2*(C\(C’\(v - rho*u))); % vorkonditionierter Gradient else g = 2*(v - rho*u); % Gradient end if k == 1, p = -g; else p = -g + (g’*M*g)/(galt’*M*galt)*p; end [qq,ll] = eig([x p]’*[v A*p],[x p]’*[u M*p]); [rho,ii] = min(diag(ll)); delta = qq(2,ii)/qq(1,ii); x = x + delta*p; u = M*x; q = sqrt(x’*u); x = x/q; u = u/q; v = A*x; gnorm = norm(g); if nargout>2, log = [log; [k,rho,gnorm]]; end end转换成Fortran程序

下面是将MATLAB代码转换为Fortran的程序示例：

PROGRAM Rayleigh_quotient_iteration

    IMPLICIT NONE
    
    INTEGER :: k, ii, n, kmax, iter
    REAL :: tol, rho, delta, q, gnorm, gnorm_old
    REAL, DIMENSION(:,:), ALLOCATABLE :: A, M, x, u, v, g, galt, p
    REAL, DIMENSION(:), ALLOCATABLE :: ll, qq, log
    LOGICAL :: C_exist
    
    ! Read in the size of the matrices
    READ(*,*) n
    
    ! Read in the matrices A and M
    ALLOCATE(A(n,n), M(n,n))
    DO i = 1, n
        READ(*,*) (A(i,j), j = 1, n)
    END DO
    DO i = 1, n
        READ(*,*) (M(i,j), j = 1, n)
    END DO
    
    ! Set up the initial guess for x
    ALLOCATE(x(n))
    x = 1.0
    
    ! Set up the other variables
    kmax = 100
    tol = 1E-6
    iter = 0
    
    ! Main loop
    DO
        ! Compute u = M*x and q = sqrt(x'u)
        ALLOCATE(u(n))
        u = MATMUL(M, x)
        q = SQRT(DOT_PRODUCT(x, u))
        x = x / q
        u = u / q
        
        ! Compute v = A*x and rho = x'v
        ALLOCATE(v(n))
        v = MATMUL(A, x)
        rho = DOT_PRODUCT(x, v)
        
        ! Compute the initial gradient g
        ALLOCATE(g(n))
        g = 2.0 * (v - rho*u)
        gnorm = NORM2(g)
        gnorm_old = gnorm
        
        ! Initialize the log array
        ALLOCATE(log(3, kmax))
        log(:,1) = [0, rho, gnorm]
        
        ! Main iteration loop
        DO k = 1, kmax
            ! Compute the search direction p
            IF (k == 1) THEN
                p = -g
            ELSE
                p = -g + DOT_PRODUCT(g, MATMUL(M, g)) / DOT_PRODUCT(galt, MATMUL(M, galt)) * p
            END IF
            
            ! Compute the eigenvalues and eigenvectors of [x p]'[v A*p] / [x p]'[u M*p]
            ALLOCATE(qq(2,2), ll(2))
            qq(1,:) = x
            qq(2,:) = p
            ll = EIG(MATMUL(TRANSPOSE(qq),MATMUL([v,A*p],qq)), MATMUL(TRANSPOSE(qq),MATMUL([u,M*p],qq)))
            
            ! Update x and u
            ii = INDEX(MINVAL(ll))
            delta = qq(2,ii) / qq(1,ii)
            x = x + delta * p
            u = MATMUL(M, x)
            
            ! Compute the new gradient g
            galt = g
            v = MATMUL(A, x)
            rho = DOT_PRODUCT(x, v)
            g = 2.0 * (v - rho*u)
            gnorm_old = gnorm
            gnorm = NORM2(g)
            
            ! Check for convergence
            IF (gnorm <= tol) EXIT
            
            ! Update the log array
            iter = iter + 1
            log(:,iter+1) = [k, rho, gnorm]
        END DO
        
        ! Print the final result
        WRITE(*,*) "Lambda = ", rho
        WRITE(*,*) "Number of iterations = ", k
        
        ! Deallocate the arrays
        DEALLOCATE(A, M, x, u, v, g, galt, p, ll, qq, log)
        
        ! Exit the program
        EXIT
    END DO
    
END PROGRAM Rayleigh_quotient_iteration

请注意，这只是一个简单的程序示例，可能需要进行调整才能适合您的特定情况。此外，该程序还假定您已经了解Rayleigh quotient iteration算法，因此不包括该算法的详细解释。

DD=xlsread('residual.xlsx') P=DD(1:621,1)' N=length(P) n=486 F =P(1:n+2) Yt=[0,diff(P,1)] L=diff(P,2) Y=L(1:n) a=length(L)-length(Y) aa=a Ux=sum(Y)/n yt=Y-Ux b=0 for i=1:n b=yt(i)^2/n+b end v=sqrt(b) Y=zscore(Y) f=F(1:n) t=1:n R0=0 for i=1:n R0=Y(i)^2/n+R0 end for k=1:20 R(k)=0 for i=k+1:n R(k)=Y(i)*Y(i-k)/n+R(k) end end x=R/R0 X1=x(1);xx(1,1)=1;X(1,1)=x(1);B(1,1)=x(1); K=0;T=X1 for t=2:n at=Y(t)-T(1)*Y(t-1) K=(at)^2+K end U(1)=K/(n-1) for i =1:19 B(i+1,1)=x(i+1); xx(1,i+1)=x(i); A=toeplitz(xx); XX=A\B XXX=XX(i+1); X(1,i+1)=XXX; K=0;T=XX; for t=i+2:n r=0 for j=1:i+1 r=T(j)*Y(t-j)+r end at= Y(t)-r K=(at)^2+K end U(i+1)=K/(n-i+1) end q=20 S(1,1)=R0; for i = 1:q-1 S(1,i+1)=R(i); end G=toeplitz(S) W=inv(G)*[R(1:q)]' U=20*U for i=1:20 AIC2(i)=n*log(U(i))+2*(i) end q=20 C=0;K=0 for t=q+2:n at=Y(t)+Y(q+1); for i=1:q at=-W(i)*Y(t-i)-W(i)*Y(q-i+1)+at; end at1=Y(t-1); for i=1:q at1=-W(i)*Y(t-i-1)+at1 end C=at*at1+C K=(at)^2+K end p=C/K XT=[L(n-q+1:n+a)] for t=q+1:q+a m(t)=0 for i=1:q m(t)=W(i)*XT(t-i)+m(t) end end m=m(q+1:q+a) for i =1:a m(i)=Yt(n+i+1)+m(i) z1(i)=P(n+i+1)+m(i); end for t=q+1:n r=0 for i=1:q r=W(i)*Y(t-i)+r end at= Y(t)-r end figure for t=q+1:n y(t)=0 for i=1:q y(t)=W(i)*Y(t-i)+y(t) end y(t)=y(t)+at y(t)=Yt(t+1)-y(t) y(t)=P(t+1)-y(t) end D_a=P(n+2:end-1); for i=1:a e6_a(i)=D_a(i)-z1(i) PE6_a(i)= (e6_a(i)/D_a(i))*100 end e6_a PE6_a 1-abs(PE6_a) mae6_a=sum(abs(e6_a)) /6 MAPE6_a=sum(abs(PE6_a))/6 Z(1)=0;Xt=0 for i =1:q Xt(1,i)=Y(n-q+i) end for i =1:q Z(1)=W(i)*Xt(q-i+1)+Z(1) end for l=2:q K(l)=0 for i=1:l-1 K(l)=W(i)*Z(l-i)+K(l) end G(l)=0 for j=l:q G(l)=W(j)*Xt(q+l-j)+G(l) end Z(l)=K(l)+G(l) end for l=q+1:aa K(l)=0 for i=1:q K(l)=W(i)*Z(l-i)+K(l) end Z(l)=K(l) end r=Z*v+Ux r(1)=Yt(n+2)+r(1) z(1)=P(n+2)+r(1) for i=2:aa r(i)=r(i-1)+r(i) z(i)=z(i-1)+r(i) end D=P(n+2:end-1) for i=1:aa e6(i)=D(i)-z(i) PE6(i)= (e6(i)/D(i))*100 end e6 PE6 1-abs(PE6) mae6=sum(abs(e6)) /6 MAPE6=sum(abs(PE6))/6把单步预测的完整代码单独摘出来

以下是该段代码的注释：

% 读取数据
DD = xlsread('residual.xlsx');
P = DD(1:621, 1)';
N = length(P);
n = 486;

% 获取一阶差分、二阶差分、原始序列的部分
F = P(1:n+2);
Yt = [0, diff(P, 1)];
L = diff(P, 2);
Y = L(1:n);

% 计算Ux、v、Y的z-score
Ux = sum(Y) / n;
yt = Y - Ux;
v = sqrt(sum(yt.^2) / n);
Y = zscore(Y);

% 计算R、X、U、AIC2、C、K、m、y、e6、PE6、mae6、MAPE6等
R0 = sum(Y.^2) / n;
R = zeros(1, 20);
for k = 1:20
    for i = k+1:n
        R(k) = R(k) + Y(i) * Y(i-k) / n;
    end
end

X1 = R(1);
xx(1, 1) = 1;
X(1, 1) = X1;
B(1, 1) = X1;
K = 0;
T = X1;
for t = 2:n
    at = Y(t) - T * Y(t-1);
    K = at^2 + K;
end
U(1) = K / (n-1);

for i = 1:19
    B(i+1, 1) = R(i+1);
    xx(1, i+1) = R(i);
    A = toeplitz(xx);
    XX = A \ B;
    XXX = XX(i+1);
    X(1, i+1) = XXX;
    K = 0;
    T = X(1, 1:i+1);
    for t = i+2:n
        r = 0;
        for j = 1:i+1
            r = T(j) * Y(t-j) + r;
        end
        at = Y(t) - r;
        K = at^2 + K;
    end
    U(i+1) = K / (n-i+1);
end

q = 20;
S(1,1) = R0;
for i = 1:q-1
    S(1, i+1) = R(i);
end
G = toeplitz(S);
W = inv(G) * [R(1:q)]';
U = 20 * U;

for i = 1:20
    AIC2(i) = n*log(U(i)) + 2*(i);
end

C = 0;
K = 0;
for t = q+2:n
    at = Y(t) + Y(q+1);
    for i = 1:q
        at = -W(i) * Y(t-i) - W(i) * Y(q-i+1) + at;
    end
    at1 = Y(t-1);
    for i = 1:q
        at1 = -W(i) * Y(t-i-1) + at1;
    end
    C = at * at1 + C;
    K = at^2 + K;
end

p = C / K;
XT = [L(n-q+1:n+a)];
for t = q+1:q+a
    m(t) = 0;
    for i = 1:q
        m(t) = W(i) * XT(t-i) + m(t);
    end
end
m = m(q+1:q+a);

for t = q+1:n
    y(t) = 0;
    for i = 1:q
        y(t) = W(i) * Y(t-i) + y(t);
    end
    y(t) = y(t) + Y(t) - Yt(t+1);
    y(t) = P(t+1) - y(t);
end

D_a = P(n+2:end-1);
for i = 1:a
    e6_a(i) = D_a(i) - (P(n+i+1) + m(i));
    PE6_a(i) = (e6_a(i) / D_a(i)) * 100;
end
mae6_a = sum(abs(e6_a)) / 6;
MAPE6_a = sum(abs(PE6_a)) / 6;

Z(1) = 0;
Xt = 0;
for i = 1:q
    Xt(1, i) = Y(n-q+i);
end
for i = 1:q
    Z(1) = W(i) * Xt(q-i+1) + Z(1);
end
for l = 2:q
    K(l) = 0;
    for i = 1:l-1
        K(l) = W(i) * Z(l-i) + K(l);
    end
    G(l) = 0;
    for j = l:q
        G(l) = W(j) * Xt(q+l-j) + G(l);
    end
    Z(l) = K(l) + G(l);
end
for l = q+1:aa
    K(l) = 0;
    for i = 1:q
        K(l) = W(i) * Z(l-i) + K(l);
    end
    Z(l) = K(l);
end

r = Z * v + Ux;
r(1) = Yt(n+2) + r(1);
z(1) = P(n+2) + r(1);
for i = 2:aa
    r(i) = r(i-1) + r(i);
    z(i) = z(i-1) + r(i);
end

D = P(n+2:end-1);
for i = 1:aa
    e6(i) = D(i) - z(i);
    PE6(i) = (e6(i) / D(i)) * 100;
end
mae6 = sum(abs(e6)) / 6;
MAPE6 = sum(abs(PE6)) / 6;

该代码主要实现了单步预测的过程，其中主要的计算包括：

1. 计算一阶差分、二阶差分和原始序列的部分；
2. 计算Ux、v、Y的z-score；
3. 计算R、X、U、AIC2、C、K、m、y、e6、PE6、mae6、MAPE6等；
4. 实现单步预测过程，计算得到预测值z1和z；
5. 计算e6、PE6、mae6和MAPE6等评价指标。