求一到二十的阶乘的和
时间: 2024-06-13 11:04:33 浏览: 11
题目要求求1到20的阶乘的和,可以使用循环来实现。每次循环计算当前数的阶乘,并将其加到之前的和中。最后输出结果即可。
代码示例:
```
int sum = 0;
int factorial = 1;
for (int i = 1; i <= 20; i++) {
factorial *= i;
sum += factorial;
}
printf("1到20的阶乘的和为:%d", sum);
```
相关问题
c语言求一到二十的阶乘的和
以下是C语言求1到20的阶乘的和的代码:
```c
#include <stdio.h>
int main() {
int i, j;
long long factorial = 1, sum = 0;
for (i = 1; i <= 20; i++) {
factorial = 1;
for (j = 1; j <= i; j++) {
factorial *= j;
}
sum += factorial;
}
printf("1! + 2! + ... + 20! = %lld\n", sum);
return 0;
}
```
运行结果为:
```
1! + 2! + ... + 20! = 2561327494111820313
```
c语言一到二十阶乘求和
以下是C语言求1到20阶乘的和的代码:
```c
#include <stdio.h>
int main() {
int i, j;
long long factorial = 1, sum = 0;
for (i = 1; i <= 20; i++) {
factorial = 1;
for (j = 1; j <= i; j++) {
factorial *= j;
}
sum += factorial; }
printf("The sum of factorials from 1 to 20 is: %lld\n", sum);
return 0;
}
```
运行结果为:
```
The sum of factorials from 1 to 20 is: 2561327494111820313
```
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