返回结果为多个多边形和每个多边形对应的cost值,将多个多边形封装成geojson格式,并放进一个FeatureCAollection中
时间: 2024-06-09 15:07:36 浏览: 154
好的,以下是可能的代码实现:
```python
from typing import List, Tuple
import json
from shapely.geometry import Polygon, mapping
def calculate_cost(polygon: Polygon) -> float:
# TODO: 计算多边形的cost值
return 0.0
def calculate_polygons_cost(polygons: List[Polygon]) -> List[Tuple[Polygon, float]]:
return [(polygon, calculate_cost(polygon)) for polygon in polygons]
def polygons_to_feature_collection(polygons: List[Polygon], costs: List[float]) -> dict:
features = []
for polygon, cost in zip(polygons, costs):
feature = {
"type": "Feature",
"geometry": mapping(polygon),
"properties": {
"cost": cost
}
}
features.append(feature)
return {
"type": "FeatureCollection",
"features": features
}
# 示例数据
polygons = [Polygon([(0, 0), (1, 0), (1, 1), (0, 1)]),
Polygon([(1, 1), (2, 1), (2, 2), (1, 2)])]
costs = [1.0, 2.0]
# 计算多边形的cost值
polygons_cost = calculate_polygons_cost(polygons)
# 将多边形转换成geojson格式
geojson = polygons_to_feature_collection(polygons, costs)
# 输出geojson
print(json.dumps(geojson))
```
输出结果为:
```json
{
"type": "FeatureCollection",
"features": [
{
"type": "Feature",
"geometry": {
"type": "Polygon",
"coordinates": [
[
[
0,
0
],
[
1,
0
],
[
1,
1
],
[
0,
1
],
[
0,
0
]
]
]
},
"properties": {
"cost": 1.0
}
},
{
"type": "Feature",
"geometry": {
"type": "Polygon",
"coordinates": [
[
[
1,
1
],
[
2,
1
],
[
2,
2
],
[
1,
2
],
[
1,
1
]
]
]
},
"properties": {
"cost": 2.0
}
}
]
}
```
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