1控制台打印“当前进入加减乘除运算”2函数命名为:“jiaFa(intx,inty),jianFa(intx,inty),chengFa(intx,inty),chuFa(intx,inty

好的，我可以回答您的问题。

1. 控制台打印“当前进入加减乘除运算”，可以使用如下代码实现：

System.out.println("当前进入加减乘除运算");

2. 函数命名为：“jiaFa(int x, int y)”，“jianFa(int x, int y)”，“chengFa(int x, int y)”，“chuFa(int x, int y)”，可以使用如下代码实现：

public int jiaFa(int x, int y) {
    return x + y;
}

public int jianFa(int x, int y) {
    return x - y;
}

public int chengFa(int x, int y) {
    return x * y;
}

public int chuFa(int x, int y) {
    if (y == 0) {
        throw new IllegalArgumentException("除数不能为0");
    }
    return x / y;
}

希望能够帮助到您！

相关问题

1控制台打印“当前进入加减乘除运算” 2函数命名为:“jiaFa(int x,int y), jianFa(int x,int y), chengFa(int x,int y), chuFa(int x,int y) 3分别写出四个函数的具体实现 4调用加减乘除函数，实现5+5 = 10，5-5=0，5*5=25,5/5=1 输出

1. 当前进入加减乘除运算

2. 四个函数命名为：

def jiaFa(x, y):
    pass

def jianFa(x, y):
    pass

def chengFa(x, y):
    pass

def chuFa(x, y):
    pass

3. 四个函数的具体实现如下：

def jiaFa(x, y):
    return x + y

def jianFa(x, y):
    return x - y

def chengFa(x, y):
    return x * y

def chuFa(x, y):
    if y == 0:
        return "除数不能为0"
    else:
        return x / y

4. 调用加减乘除函数，实现5+5 = 10，5-5=0，5*5=25,5/5=1 的代码如下：

a = 5
b = 5

print("5 + 5 =", jiaFa(a, b))
print("5 - 5 =", jianFa(a, b))
print("5 * 5 =", chengFa(a, b))
print("5 / 5 =", chuFa(a, b))

输出结果为：

5 + 5 = 10
5 - 5 = 0
5 * 5 = 25
5 / 5 = 1.0

#include <bits/stdc++.h> using namespace std; string jiafa(string s1, string s2) { string ans2 = ""; int t1, t2, ans1 = 0, up = 0; reverse(s1.begin(), s1.end()); reverse(s2.begin(), s2.end()); while (s1.length() != s2.length()) { if (s1.length() > s2.length()) s2 += '0'; else if (s1.length() < s2.length()) s1 += '0'; } cout << endl << s1 << endl << s2 << endl; for (int i = 0; i < s1.length() - 1; i++) { t1 = stoi(string(1, s1[i])); t2 = stoi(string(1, s1[i])); ans1 = t1 + t2 + up; if (ans1 >= 10) { ans1 %= 10; up = 1; } else up = 0; ans2 += static_cast<char>(ans1 + 48); } reverse(ans2.begin(), ans2.end()); return ans2; } int main() { string s1, s2; cin >> s1 >> s2; cout << jiafa(s1, s2); return 0; }纠正代码

下面是修改后的代码，主要是修正了变量t2的赋值错误，以及for循环中的终止条件错误：

#include <bits/stdc++.h>
using namespace std;

string jiafa(string s1, string s2) {
    string ans2 = "";
    int t1, t2, ans1 = 0, up = 0;
    reverse(s1.begin(), s1.end());
    reverse(s2.begin(), s2.end());
    while (s1.length() != s2.length()) {
        if (s1.length() > s2.length())
            s2 += '0';
        else if (s1.length() < s2.length())
            s1 += '0';
    }
    cout << endl << s1 << endl << s2 << endl;
    for (int i = 0; i < s1.length(); i++) {
        t1 = stoi(string(1, s1[i]));
        t2 = stoi(string(1, s2[i])); // 修改这里的赋值错误
        ans1 = t1 + t2 + up;
        if (ans1 >= 10) {
            ans1 %= 10;
            up = 1;
        } else
            up = 0;
        ans2 += static_cast<char>(ans1 + 48);
    }
    reverse(ans2.begin(), ans2.end());
    return ans2;
}

int main() {
    string s1, s2;
    cin >> s1 >> s2;
    cout << jiafa(s1, s2);
    return 0;
}