使用字典来创建程序,提示用户输人一个整数,并用英文单词形式来显示数字。例如:输人 138 显示为“one three eight"
时间: 2023-06-04 19:07:03 浏览: 142
Sure, I can help you with that. Here's the Python code to convert a given integer to its English word equivalent using a dictionary:
```
num_words = {
0: 'zero',
1: 'one',
2: 'two',
3: 'three',
4: 'four',
5: 'five',
6: 'six',
7: 'seven',
8: 'eight',
9: 'nine'
}
num = input("Enter an integer: ")
word = ""
for digit in num:
word += num_words[int(digit)] + " "
print(word.strip())
```
This code takes an integer input from the user, converts it to its English word equivalent using the `num_words` dictionary, and prints it out. For example, entering "138" would output "one three eight".
相关问题
用python实现使用字典编写一个程序,用户输入一个月份,程序输出该月份对应的英文单词
好的,我可以帮你实现这个程序。以下是代码实现:
```
# 定义一个字典,存储月份和对应的英文单词
month_dict = {
"1": "January",
"2": "February",
"3": "March",
"4": "April",
"5": "May",
"6": "June",
"7": "July",
"8": "August",
"9": "September",
"10": "October",
"11": "November",
"12": "December"
}
# 获取用户输入的月份
month = input("Please enter a month number (1-12): ")
# 判断输入是否为合法月份
if month in month_dict:
# 输出对应的英文单词
print("The month is", month_dict[month])
else:
print("Invalid input!")
```
使用时,用户输入一个月份的数字(1-12),程序会输出该月份对应的英文单词。如果输入的数字不在1-12之间,则输出"Invalid input!"。
Python使用字典编写一个程序,用户输入一个英文句子,统计每个单词出现的次数
好的,这是一个程序设计问题,我可以回答。以下是Python代码示例:
```
sentence = input("请输入一个英文句子:")
words = sentence.split()
word_count = {}
for word in words:
if word in word_count:
word_count[word] += 1
else:
word_count[word] = 1
print("单词出现的次数:")
for word in word_count:
print(word + ": " + str(word_count[word]))
```
用户输入一个英文句子,该程序将其拆分成单词,然后使用字典来记录每个单词出现的次数,最后显示每个单词及其出现次数。
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