n,S = map(int,input().split()) a = list(map(int,input().split())) sum = 0 ans = le8
时间: 2024-06-04 21:14:03 浏览: 14
n, S = map(int, input().split())
a = list(map(int, input().split()))
sum = 0
ans = float('inf')
# Iterate through all possible subarrays
for i in range(n):
sum = a[i]
# Check if the current element is already greater than S
if sum >= S:
ans = 1
break
j = i + 1
# Add elements to the sum until it becomes greater than or equal to S
while j < n and sum < S:
sum += a[j]
j += 1
# If the current subarray has a sum greater than or equal to S, update the answer
if sum >= S:
ans = min(ans, j-i)
# If no subarray has a sum greater than or equal to S, print -1
if ans == float('inf'):
print(-1)
else:
print(ans)
相关问题
list1=map(int(input().split()))
list1=map(int,input().split())的含义是将用户输入的一行数字字符串按空格分割成多个数字,并将这些数字转化为整型,然后将它们存储在一个迭代器对象中。这个迭代器对象可以通过list()函数转化为列表,或者直接在循环中使用。下面是一个示例代码:
```python
list1 = list(map(int, input().split()))
print(list1)
```
用户输入:1 2 3 4
输出:[1, 2, 3, 4]
s=list(map(int,input().split()))
s=list(map(int,input().split())) 的作用是将用户输入的一行数字字符串按空格分割成多个数字,并将这些数字存储在一个列表中。这行代码首先使用 input() 函数获取用户输入的一行字符串,然后使用 split() 函数将其按空格分割成多个子字符串,再使用 map() 函数将每个子字符串转换为整数,最后将这些整数存储在一个列表中。<span class="em">1</span><span class="em">2</span><span class="em">3</span>
#### 引用[.reference_title]
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