map.count()

map.count()是C++中map容器的成员函数，用于返回指定键的出现次数。如果指定的键存在于map中，则返回1；如果指定的键不存在于map中，则返回0。\[1\]\[2\]
#### 引用[.reference_title]
- *1* [C++ map中的count()方法](https://blog.csdn.net/lemn_de/article/details/119325232)[target="_blank" data-report-click={"spm":"1018.2226.3001.9630","extra":{"utm_source":"vip_chatgpt_common_search_pc_result","utm_medium":"distribute.pc_search_result.none-task-cask-2~all~insert_cask~default-1-null.142^v91^insertT0,239^v3^insert_chatgpt"}} ] [.reference_item]
- *2* [C++ map count()用法及代码示例](https://blog.csdn.net/weixin_64632836/article/details/127744751)[target="_blank" data-report-click={"spm":"1018.2226.3001.9630","extra":{"utm_source":"vip_chatgpt_common_search_pc_result","utm_medium":"distribute.pc_search_result.none-task-cask-2~all~insert_cask~default-1-null.142^v91^insertT0,239^v3^insert_chatgpt"}} ] [.reference_item]
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