[i+1 for i in range(TOTAL_NUMBER)]
时间: 2024-05-24 21:10:40 浏览: 14
This is a list comprehension that creates a list of integers from 1 to TOTAL_NUMBER.
For example, if TOTAL_NUMBER = 5, the output would be [1, 2, 3, 4, 5].
The syntax of the list comprehension is as follows:
- [expression for variable in iterable]
- The expression is what we want to do with each element in the iterable (in this case, we want to return i).
- The variable is the name we give to each element in the iterable as we iterate through it (in this case, we use i).
- The iterable is the sequence of values that we want to iterate over (in this case, we use the range function to create a sequence of integers from 0 to TOTAL_NUMBER-1).
相关问题
for epoch in range(1, epochs+1):
It looks like there is a typo in the code you provided. The correct syntax should be:
```
for epoch in range(1, epochs + 1):
```
This code initializes a loop that will run for a specified number of epochs. The variable `epochs` should be defined earlier in the code, and it represents the total number of epochs that the model will be trained for.
During each epoch, the model will iterate through the training data, making predictions and adjusting its parameters to minimize the loss function. At the end of each epoch, the model's performance is evaluated on a separate validation set to check for overfitting.
import csv codon_counts = {} with open('D:/QLNU/writing/homework/BI/2022-2023第二学期作业/20230607/hORFeome_V8.1.fasta', 'r') as f: dna_sequence = f.read().replace('\n', '') # count the occurrences of each codon codon_counts = {dna_sequence[i:i+3]: codon_counts.get(dna_sequence[i:i+3], 0) + 1 for i in range(0, len(dna_sequence), 3)} #calculate the total number of codons total_codons = sum(codon_counts.values()) codon_frequencies = {} for codon in codon_counts: codon_frequencies[codon] = codon_counts[codon] / total_codons # write the results to the output file with open('D:/QLNU/writing/homework/BI/2022-2023第二学期作业/20230607/out.CSV', 'w', newline='') as f_out: writer = csv.writer(f_out) writer.writerow(['Codon', 'Frequency']) for codon in codon_frequencies: writer.writerow([codon, codon_frequencies[codon]])优化一下代码,使其读文件时从第二行开始隔行读取
import csv
codon_counts = {}
with open('D:/QLNU/writing/homework/BI/2022-2023第二学期作业/20230607/hORFeome_V8.1.fasta', 'r') as f:
# skip the first line
next(f)
# read every other line
dna_sequence = ''.join(line.strip() for i, line in enumerate(f) if i % 2 == 0)
# count the occurrences of each codon
codon_counts = {dna_sequence[i:i+3]: codon_counts.get(dna_sequence[i:i+3], 0) + 1 for i in range(0, len(dna_sequence), 3)}
# calculate the total number of codons
total_codons = sum(codon_counts.values())
codon_frequencies = {}
for codon in codon_counts:
codon_frequencies[codon] = codon_counts[codon] / total_codons
# write the results to the output file
with open('D:/QLNU/writing/homework/BI/2022-2023第二学期作业/20230607/out.CSV', 'w', newline='') as f_out:
writer = csv.writer(f_out)
writer.writerow(['Codon', 'Frequency'])
for codon in codon_frequencies:
writer.writerow([codon, codon_frequencies[codon]])
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