vs2022c++扫雷代码
时间: 2023-10-03 07:05:13 浏览: 153
以下是一个简单的 C++ 扫雷游戏的代码示例,适用于 Visual Studio 2022:
```c++
#include <iostream>
#include <cstdlib>
#include <ctime>
using namespace std;
const int ROWS = 9;
const int COLS = 9;
const int MINES = 10;
const char COVER = '#';
const char FLAG = 'F';
const char MINE = '*';
void printBoard(char board[][COLS], bool showMines = false)
{
// 打印扫雷棋盘
cout << " ";
for (int i = 0; i < COLS; ++i)
cout << i << " ";
cout << endl;
for (int i = 0; i < ROWS; ++i)
{
cout << i << " ";
for (int j = 0; j < COLS; ++j)
if (board[i][j] == MINE && !showMines) // 如果不显示地雷并且该格是地雷,打印覆盖符号
cout << COVER << " ";
else // 否则打印该格的内容
cout << board[i][j] << " ";
cout << endl;
}
}
void initBoard(char board[][COLS])
{
// 初始化扫雷棋盘
for (int i = 0; i < ROWS; ++i)
for (int j = 0; j < COLS; ++j)
board[i][j] = COVER;
}
void placeMines(char board[][COLS])
{
// 随机放置地雷
srand(time(nullptr)); // 使用当前时间作为随机数种子
int count = 0;
while (count < MINES)
{
int x = rand() % ROWS;
int y = rand() % COLS;
if (board[x][y] != MINE) // 如果该位置没有地雷,放置地雷
{
board[x][y] = MINE;
++count;
}
}
}
void updateBoard(char board[][COLS], int row, int col)
{
// 更新扫雷棋盘
if (board[row][col] == MINE) // 如果踩到了地雷,游戏结束
{
printBoard(board, true);
cout << "You lose!" << endl;
exit(0);
}
else // 否则统计周围地雷数量并更新棋盘
{
int minesCount = 0;
for (int i = row - 1; i <= row + 1; ++i)
for (int j = col - 1; j <= col + 1; ++j)
if (i >= 0 && i < ROWS && j >= 0 && j < COLS && board[i][j] == MINE)
++minesCount;
if (minesCount > 0) // 如果周围有地雷,显示地雷数量
board[row][col] = minesCount + '0';
else // 否则递归更新周围的格子
{
board[row][col] = ' ';
for (int i = row - 1; i <= row + 1; ++i)
for (int j = col - 1; j <= col + 1; ++j)
if (i >= 0 && i < ROWS && j >= 0 && j < COLS && board[i][j] == COVER)
updateBoard(board, i, j);
}
}
}
int main()
{
char board[ROWS][COLS];
initBoard(board);
placeMines(board);
printBoard(board);
while (true)
{
int row, col;
cout << "Enter row and column: ";
cin >> row >> col;
if (board[row][col] == FLAG) // 如果该位置已经标记为地雷,取消标记
board[row][col] = COVER;
else if (board[row][col] == COVER) // 如果该位置未被翻开,更新扫雷棋盘
updateBoard(board, row, col);
else // 否则提示该位置已经被翻开
cout << "This cell has already been flipped!" << endl;
printBoard(board);
}
return 0;
}
```
注意:这只是一个简单的示例代码,可能存在一些问题和不完善的地方。如果您想要编写更完善的扫雷游戏,建议参考更全面的教程或者借助第三方游戏引擎。
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