用py制作一个具有上下题功能的答题系统

可以使用Python的tkinter库来制作具有上下题功能的答题系统。下面是一个简单的示例代码，你可以根据自己的需求进行修改和完善：

from tkinter import *
from tkinter import messagebox

# 定义题目和答案
questions = [
    {"question": "1+1=?", "options": ["1", "2", "3", "4"], "answer": "2"},
    {"question": "2+2=?", "options": ["2", "3", "4", "5"], "answer": "4"},
    {"question": "3+3=?", "options": ["4", "5", "6", "7"], "answer": "6"},
    {"question": "4+4=?", "options": ["6", "7", "8", "9"], "answer": "8"},
    {"question": "5+5=?", "options": ["8", "9", "10", "11"], "answer": "10"}
]

# 定义变量
current_question = 0
score = 0

# 定义函数
def show_question():
    global current_question
    question = questions[current_question]
    question_label.config(text=question["question"])
    option1.config(text=question["options"][0])
    option2.config(text=question["options"][1])
    option3.config(text=question["options"][2])
    option4.config(text=question["options"][3])

def check_answer(answer):
    global current_question
    global score
    question = questions[current_question]
    if question["answer"] == answer:
        score += 1
    current_question += 1
    if current_question == len(questions):
        messagebox.showinfo("答题完成", f"您的得分为{score}分")
        root.destroy()
    else:
        show_question()

def previous_question():
    global current_question
    if current_question > 0:
        current_question -= 1
        show_question()

def next_question():
    global current_question
    if current_question < len(questions) - 1:
        current_question += 1
        show_question()

# 创建窗口和控件
root = Tk()
root.title("答题系统")

question_label = Label(root, text="")
question_label.pack()

option1 = Button(root, text="", command=lambda: check_answer(questions[current_question]["options"][0]))
option1.pack()

option2 = Button(root, text="", command=lambda: check_answer(questions[current_question]["options"][1]))
option2.pack()

option3 = Button(root, text="", command=lambda: check_answer(questions[current_question]["options"][2]))
option3.pack()

option4 = Button(root, text="", command=lambda: check_answer(questions[current_question]["options"][3]))
option4.pack()

previous_button = Button(root, text="上一题", command=previous_question)
previous_button.pack(side=LEFT)

next_button = Button(root, text="下一题", command=next_question)
next_button.pack(side=RIGHT)

show_question()

root.mainloop()

在这个示例代码中，我们首先定义了题目和答案，然后创建了窗口和控件。在控件中，我们使用了`Label`控件显示题目，使用`Button`控件作为选项，并且为每个选项绑定了一个回调函数，在点击选项时会检查答案是否正确，并且切换到下一题。同时，我们还创建了“上一题”和“下一题”两个按钮，通过点击这两个按钮可以切换当前显示的题目。在检查答案时，如果当前已经是最后一题，则会弹出一个消息框显示最终得分，并且退出程序。

你可以在这个示例代码的基础上进行修改和扩展，添加更多的题目和选项，或者改变题目和选项的显示方式。