写一段python代码，实现根据音频名称，将好几段音频拼接

以下为一种实现方法：

import os
import librosa

def concatenate_audio(audio_names, output_name):
    # audio_names: a list of audio file names to be concatenated
    # output_name: the name of the output concatenated audio file
    
    audio_data = []
    sr = None
    
    for audio_name in audio_names:
        # load audio data
        audio_path = os.path.join('audio_path', audio_name) # replace 'audio_path' with the path of the audio files
        data, current_sr = librosa.load(audio_path, sr=None)
        
        # resample to the same sample rate
        if sr is None:
            sr = current_sr
        elif sr != current_sr:
            data = librosa.resample(data, current_sr, sr)
        
        audio_data.append(data)
    
    # concatenate audio data
    concatenated_data = librosa.util.buf_to_pad(audio_data)
    
    # save concatenated audio
    output_path = os.path.join('output_path', output_name) # replace 'output_path' with the path to save the output file
    librosa.output.write_wav(output_path, concatenated_data, sr=sr)

使用方法：

audio_names = ['audio1.wav', 'audio2.wav', 'audio3.wav']
output_name = 'concatenated_audio.wav'

concatenate_audio(audio_names, output_name)

其中，`audio_names`为需要拼接的音频文件名列表，`output_name`为拼接后输出的文件名。需要将代码中的`'audio_path'`和`'output_path'`替换为实际的路径。此外，代码中假设所有音频文件的采样率相同，如有不同需要进行采样率转换。