C++ transpose

Sure, I can help you with that!

To transpose a matrix in C++, you can use nested loops to iterate over the rows and columns of the matrix. Here's an example code snippet:

#include <iostream>

const int ROWS = 3;
const int COLS = 3;

void transposeMatrix(int mat[ROWS][COLS]) {
    int transposedMat[COLS][ROWS];

    // Transpose the matrix
    for (int i = 0; i < ROWS; ++i) {
        for (int j = 0; j < COLS; ++j) {
            transposedMat[j][i] = mat[i][j];
        }
    }

    // Print the transposed matrix
    for (int i = 0; i < COLS; ++i) {
        for (int j = 0; j < ROWS; ++j) {
            std::cout << transposedMat[i][j] << " ";
        }
        std::cout << std::endl;
    }
}

int main() {
    int matrix[ROWS][COLS] = {{1, 2, 3},
                              {4, 5, 6},
                              {7, 8, 9}};
                              
    std::cout << "Original Matrix:" << std::endl;
    for (int i = 0; i < ROWS; ++i) {
        for (int j = 0; j < COLS; ++j) {
            std::cout << matrix[i][j] << " ";
        }
        std::cout << std::endl;
    }
    
    std::cout << "Transposed Matrix:" << std::endl;
    transposeMatrix(matrix);

    return 0;
}

This code defines a `transposeMatrix` function that takes a 2D array as input and prints its transposed matrix. In the `main` function, we define a sample matrix and print both the original and transposed matrices.

When you run this code, you will get the following output:

Original Matrix:
1 2 3
4 5 6
7 8 9
Transposed Matrix:
1 4 7
2 5 8
3 6 9

I hope this helps! Let me know if you have any further questions.