使用VHDL实现某像素与相邻8个像素的锐化运算
时间: 2024-02-22 19:55:04 浏览: 25
好的,以下是一个简单的VHDL实现某像素与相邻8个像素的锐化运算的代码:
```vhdl
library IEEE;
use IEEE.STD_LOGIC_1164.ALL;
use IEEE.NUMERIC_STD.ALL;
entity sharpen_filter is
Port ( pixel : in signed(7 downto 0);
north : in signed(7 downto 0);
north_e : in signed(7 downto 0);
east : in signed(7 downto 0);
south_e : in signed(7 downto 0);
south : in signed(7 downto 0);
south_w : in signed(7 downto 0);
west : in signed(7 downto 0);
north_w : in signed(7 downto 0);
result : out signed(7 downto 0));
end sharpen_filter;
architecture Behavioral of sharpen_filter is
signal sum : signed(9 downto 0);
begin
sum <= (pixel * 8) - north - north_e - east - south_e - south - south_w - west - north_w;
result <= sum(7 downto 0);
end Behavioral;
```
这段代码实现了某像素与相邻8个像素的锐化运算。我们将像素及其相邻的8个像素作为输入,使用一个9位的有符号数来存储它们的加权和。这里我们采用了一个简单的锐化算法,即将像素乘以8并减去相邻像素的和。最后将结果输出到“result”信号中。