#include <iostream> #include <ctime> using namespace std; struct student { int id; char gender; student* next; }; void twoQueue(student* hybrid, student*& girls, student*& boys); void output(student* girls, student* boys); void in(student* h, student* t); student* insert(student* head, student* t); int main() { int num; cin >> num; student* hybrid = NULL, * hybridCur = NULL, * tmp; for (int i = 0; i < num; i++) { tmp = new student; cin >> tmp->id >> tmp->gender; tmp->next = NULL; if (hybridCur == NULL) { hybridCur = tmp; hybrid = hybridCur; } else { hybridCur->next = tmp; hybridCur = hybridCur->next; } } student* girls = NULL, * boys = NULL; twoQueue(hybrid, girls, boys); output(girls, boys); } student* insert(student* head, student* t) { // 请在此添加代码，补全函数insertTail /********** Begin *********/ if (head == NULL) { t->next = NULL; return t; } student* cur = head; while (cur->next != NULL) { cur = cur->next; } cur->next = t; t->next = NULL; return head; /********** End **********/ } void in(student* h, student* t) { if (h == NULL) { t->next = NULL; h = t; } else { student* cur = h; while (cur->next) { cur = cur->next; } cur->next = t; t->next = NULL; } } void twoQueue(student* hybrid, student*& girls, student*& boys) { /**********Program**********/ student* cur = hybrid; student* pre = hybrid; student* g = girls; student* b = boys; int c = 0; while (cur) { if (cur->gender == 'F') { cur = cur->next; pre->next = NULL; in(girls, pre); c++; } else if (cur->gender == 'M') { cur = cur->next; pre->next = NULL; in(boys, pre); //cout << c << " " << pre->id << endl;// c++; } pre = cur; } /********** End **********/ } void output(student* girls, student* boys) { while (girls && girls->next) { cout << girls->id << ","; girls = girls->next; } if (girls) cout << girls->id << ";"; while (boys && boys->next) { cout << boys->id << ","; boys = boys->next; } if (boys) cout << boys->id << endl; }请帮我检查代码的错误

代码中存在一个问题，就是 `in` 函数对链表的头指针进行了修改，但是这个修改不会被传递到函数外部。因此，当 `in` 函数返回时，链表的头指针仍然是原来的值，没有被修改。

为了解决这个问题，`in` 函数的第一个参数应该是一个指向指针的指针（即 `student** h`），这样在函数内部就可以通过修改指针的值来改变链表头指针的值。

修改后的 `in` 函数代码如下：

void in(student** h, student* t) {
    if (*h == NULL) {
        t->next = NULL;
        *h = t;
    }
    else {
        student* cur = *h;
        while (cur->next) {
            cur = cur->next;
        }
        cur->next = t;
        t->next = NULL;
    }
}

另外，`insert` 函数没有被调用，可以将其删除。

相关问题

#include <stdio.h> #include<iostream> using namespace std; struct student { char id[11]; }; int main() { student s; s.id = "18048057292" ; cout << s.id << endl; system("pause"); return 0; }

这段代码是错误的，因为结构体的成员变量id是一个字符数组（字符串），不能像普通的变量一样直接赋值。应该使用strcpy函数将字符串赋值给id变量，如下所示：

#include <stdio.h>
#include <iostream>
#include <string.h>

using namespace std;

struct student {
    char id[11];
};

int main() {
    student s;
    strcpy(s.id, "18048057292");
    cout << s.id << endl;
    system("pause");
    return 0;
}

这样就可以正确地输出学生的学号了。

指出下面程序中的错误，说明错误的原因，并进行改正 #include <iostream>using namespace std;class Student {public: char name[10]; int age; float aver; void printStu();};int main() { Student p1，p2,p3; p1.age = 30; return 0;}

该程序存在两个错误，包括：

1. `#include <iostream>using namespace std;` 应改为 `#include <iostream> using namespace std;`
2. `Student p1，p2,p3;` 中的逗号应该为英文逗号，否则编译器将无法正确识别变量声明。应改为 `Student p1, p2, p3;`

改正后的代码如下：

#include <iostream>
using namespace std;

class Student {
public:
    char name[10];
    int age;
    float aver;
    void printStu();
};

int main() {
    Student p1, p2, p3;
    p1.age = 30;
    return 0;
}