for index1, itme1 in enumerate(list_col): for index, itme in enumerate(list_row): if itme1 == '总计': count = count_conditions( teacher_arr, lambda row: row[9] == '学前' or row[9] == '小学', lambda row: row[8] == itme) if count != 0: sh_4149.cell(index1+6, index+4).value = count if itme1 == '女': count = count_conditions( teacher_arr, lambda row: row[2] == '女', lambda row: row[8] == itme) if count != 0: sh_4149.cell(index1+6, index+4).value = count if itme1 == '少数民族': count = count_conditions( teacher_arr, lambda row: row[11] != '汉族', lambda row: row[8] == itme) if count != 0: sh_4149.cell(index1+6, index+4).value = count if itme1 == '在编人员': count = count_conditions( teacher_arr, lambda row: row[12] == '是', lambda row: row[8] == itme) if count != 0: sh_4149.cell(index1+6, index+4).value = count代码优化
时间: 2023-06-09 14:07:27 浏览: 42
针对这段代码,如果要进行优化,可以考虑以下几个方面:
1. 代码重构:将重复的代码抽取出来放到一个函数中,减少冗余代码,提高代码的复用性。
2. 简化条件语句:使用更简洁的条件语句,如使用if-elif语句来代替多个if语句串联。
3. 并行处理:将每个条件的计算放到一个独立的进程或线程中进行计算,提高代码的并行性能。
4. 缓存计算结果:将计算结果缓存到内存中,避免重复计算,在后续执行中直接从缓存中获取结果。
5. 使用更高效的数据结构:使用更高效的数据结构,如numpy或pandas来代替列表等数据结构,提高数据处理的效率。
6. 代码优化工具:使用代码优化工具,如使用python自带的cProfile来分析代码瓶颈,寻找优化方向和重点。
相关问题
if itme1 == '小学': count = count_conditions( change_student_arr, lambda row: row[6] == itme1, lambda row: row[4] == itme) if count != 0: sh_3040.cell(index1+7, index+6).value = count if itme1 == '女': count = count_conditions( change_student_arr, lambda row: row[2] == itme1, lambda row: row[4] == itme) if count != 0: sh_3040.cell(index1+7, index+6).value = count if itme1 == '少数民族': count = count_conditions( change_student_arr, lambda row: row[3] == itme1, lambda row: row[4] == itme) if count != 0: sh_3040.cell(index1+7, index+6).value = count代码优化
ChitGPT:您好!关于您的代码,我可以提供一些改进意见。首先,可以将多个if语句合并成一个,以减少冗余代码。具体来说,请尝试以下改进:
count = 0
if itme1 == '小学':
count = count_conditions(change_student_arr, lambda row: row[6] == itme1, lambda row: row[4] == itme)
elif itme1 == '女':
count = count_conditions(change_student_arr, lambda row: row[2] == itme1, lambda row: row[4] == itme)
elif itme1 == '少数民族':
count = count_conditions(change_student_arr, lambda row: row[3] == itme1, lambda row: row[4] == itme)
if count != 0:
sh_3040.cell(index1 7, index 6).value = count
这样可以让代码更加简洁清晰,同时还能提高代码的可读性和可维护性。如果您有任何问题或者需要我帮忙进行其他的改进,欢迎随时告诉我。
if index==1: count = count_conditions( teacher_arr, lambda row: row[3] <24, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==2: count = count_conditions( teacher_arr, lambda row: row[3] >24 and lambda row: row[3] <30, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==3: count = count_conditions( teacher_arr, lambda row: row[3] >29 and lambda row: row[3] <35, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==4: count = count_conditions( teacher_arr, lambda row: row[3] >34 and lambda row: row[3] <40, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==5: count = count_conditions( teacher_arr, lambda row: row[3] >39 and lambda row: row[3] <45, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==6: count = count_conditions( teacher_arr, lambda row: row[3] >44 and lambda row: row[3] <50, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==7: count = count_conditions( teacher_arr, lambda row: row[3] >49 and lambda row: row[3] <55, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==8: count = count_conditions( teacher_arr, lambda row: row[3] >54 and lambda row: row[3] <60, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==8: count = count_conditions( teacher_arr, lambda row: row[3] >54 and lambda row: row[3] <60, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==9: count = count_conditions( teacher_arr, lambda row: row[3] >=60, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass 优化代码
您的代码可以通过使用循环和列表,来避免重复的代码。以下是一种重构方案:
```
age_ranges = [(0, 24), (24, 30), (30, 35), (35, 40), (40, 45), (45, 50), (50, 55), (55, 60), (60, 100)]
counts = []
for i, age_range in enumerate(age_ranges):
if i == index - 1:
count = count_conditions(teacher_arr,
lambda row: age_range[0] < row[3] < age_range[1],
lambda row: row[11] == item1,
lambda row: row[8] == '专任教师')
counts.append(count)
else:
counts.append(0)
```
这样,您就可以通过循环和列表,避免重复的代码,并且可以更加清晰和易读。