for index1, itme1 in enumerate(list_col): for index, itme in enumerate(list_row): if itme1 == '总计': count = count_conditions( teacher_arr, lambda row: row[9] == '学前' or row[9] == '小学', lambda row: row[8] == itme) if count != 0: sh_4149.cell(index1+6, index+4).value = count if itme1 == '女': count = count_conditions( teacher_arr, lambda row: row[2] == '女', lambda row: row[8] == itme) if count != 0: sh_4149.cell(index1+6, index+4).value = count if itme1 == '少数民族': count = count_conditions( teacher_arr, lambda row: row[11] != '汉族', lambda row: row[8] == itme) if count != 0: sh_4149.cell(index1+6, index+4).value = count if itme1 == '在编人员': count = count_conditions( teacher_arr, lambda row: row[12] == '是', lambda row: row[8] == itme) if count != 0: sh_4149.cell(index1+6, index+4).value = count代码优化

针对这段代码，如果要进行优化，可以考虑以下几个方面：

1. 代码重构：将重复的代码抽取出来放到一个函数中，减少冗余代码，提高代码的复用性。

2. 简化条件语句：使用更简洁的条件语句，如使用if-elif语句来代替多个if语句串联。

3. 并行处理：将每个条件的计算放到一个独立的进程或线程中进行计算，提高代码的并行性能。

4. 缓存计算结果：将计算结果缓存到内存中，避免重复计算，在后续执行中直接从缓存中获取结果。

5. 使用更高效的数据结构：使用更高效的数据结构，如numpy或pandas来代替列表等数据结构，提高数据处理的效率。

6. 代码优化工具：使用代码优化工具，如使用python自带的cProfile来分析代码瓶颈，寻找优化方向和重点。

相关问题

if index==1: count = count_conditions( teacher_arr, lambda row: row[3] <24, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==2: count = count_conditions( teacher_arr, lambda row: row[3] >24 and lambda row: row[3] <30, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==3: count = count_conditions( teacher_arr, lambda row: row[3] >29 and lambda row: row[3] <35, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==4: count = count_conditions( teacher_arr, lambda row: row[3] >34 and lambda row: row[3] <40, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==5: count = count_conditions( teacher_arr, lambda row: row[3] >39 and lambda row: row[3] <45, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==6: count = count_conditions( teacher_arr, lambda row: row[3] >44 and lambda row: row[3] <50, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==7: count = count_conditions( teacher_arr, lambda row: row[3] >49 and lambda row: row[3] <55, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==8: count = count_conditions( teacher_arr, lambda row: row[3] >54 and lambda row: row[3] <60, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==8: count = count_conditions( teacher_arr, lambda row: row[3] >54 and lambda row: row[3] <60, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass if index==9: count = count_conditions( teacher_arr, lambda row: row[3] >=60, lambda row: row[11] == itme1, lambda row: row[8] == '专任教师') pass

你的问题是关于一个Python代码片段的，它根据条件计算教师人数。在这个代码片段中，有多个if语句，每个if语句都根据不同的年龄范围和其它条件计算教师人数。具体来说，如果index等于1，那么代码将统计年龄小于24岁、专任教师且科目为itme1的教师人数；如果index等于2，那么代码将统计年龄在24岁到30岁之间、专任教师且科目为itme1的教师人数；以此类推。需要提醒的是，代码片段中的每个lambda表达式都是用来筛选满足条件的行的。

if itme1 == '小学': count = count_conditions( change_student_arr, lambda row: row[6] == itme1, lambda row: row[4] == itme) if count != 0: sh_3040.cell(index1+7, index+6).value = count if itme1 == '女': count = count_conditions( change_student_arr, lambda row: row[2] == itme1, lambda row: row[4] == itme) if count != 0: sh_3040.cell(index1+7, index+6).value = count if itme1 == '少数民族': count = count_conditions( change_student_arr, lambda row: row[3] == itme1, lambda row: row[4] == itme) if count != 0: sh_3040.cell(index1+7, index+6).value = count代码优化

ChitGPT：您好！关于您的代码，我可以提供一些改进意见。首先，可以将多个if语句合并成一个，以减少冗余代码。具体来说，请尝试以下改进：

count = 0
if itme1 == '小学':
count = count_conditions(change_student_arr, lambda row: row[6] == itme1, lambda row: row[4] == itme)
elif itme1 == '女':
count = count_conditions(change_student_arr, lambda row: row[2] == itme1, lambda row: row[4] == itme)
elif itme1 == '少数民族':
count = count_conditions(change_student_arr, lambda row: row[3] == itme1, lambda row: row[4] == itme)

if count != 0:
sh_3040.cell(index1 7, index 6).value = count

这样可以让代码更加简洁清晰，同时还能提高代码的可读性和可维护性。如果您有任何问题或者需要我帮忙进行其他的改进，欢迎随时告诉我。