使用matlab写一个算法实现以下要求：首先画一个含有多边形岛屿以及一个圆形岛屿的型腔，然后，通过一系列的平行线与型腔以及岛屿的轮廓边界进行求交，并将交点存储起来，按照一定的算法，将这些交点顺次连接起来，要求是这些交点连起来的线避开岛屿，请给我写一个可以参考的matlab代码

以下是一个可以参考的 Matlab 代码，实现了你的要求：

% 定义岛屿轮廓
island1 = [2, 2; 8, 2; 8, 6; 4, 6; 4, 4; 2, 4];
island2 = [12, 4; 14, 4; 14, 6; 12, 6];
island = [island1; island2];
% 定义圆形岛屿
center = [10, 10];
radius = 2;
t = linspace(0, 2*pi, 50)';
circle = [center(1)+radius*cos(t), center(2)+radius*sin(t)];
% 绘制岛屿轮廓和圆形岛屿
figure;
hold on;
plot(island(:,1), island(:,2), 'k');
plot(circle(:,1), circle(:,2), 'k');
axis equal;
% 定义平行线的间距和数量
distance = 0.5;
num_lines = 20;
% 求出岛屿轮廓和圆形岛屿与平行线的交点
points = [];
for i = 1:num_lines
    y = i*distance;
    line = [0, y; 20, y];
    intersections = intersectPolygons(line, island);
    intersections = [intersections; intersectCircle(line, circle)];
    points = [points; intersections];
end
% 按照一定的算法，将这些交点顺次连接起来，并避开岛屿
path = connectPoints(points, island);
% 绘制路径
plot(path(:,1), path(:,2), 'r');

其中，`intersectPolygons` 和 `intersectCircle` 分别是求多边形和圆形与直线的交点的函数，`connectPoints` 是将交点顺次连接起来的函数。这些函数的实现可以参考下面的代码：

function intersections = intersectPolygons(line, polygon)
% 求多边形和直线的交点
intersections = [];
for i = 1:size(polygon,1)
    p1 = polygon(i,:);
    j = i+1;
    if j > size(polygon,1)
        j = 1;
    end
    p2 = polygon(j,:);
    intersection = intersectLineSegments(line, [p1; p2]);
    if ~isempty(intersection)
        intersections = [intersections; intersection];
    end
end
end

function intersections = intersectCircle(line, circle)
% 求圆形和直线的交点
a = line(1,:);
b = line(2,:);
c = circle(1,:);
r = norm(circle(2,:)-circle(1,:));
d = b-a;
f = a-c;
a2 = sum(d.^2);
b2 = 2*dot(f,d);
c2 = sum(f.^2)-r^2;
discriminant = b2^2 - 4*a2*c2;
if discriminant >= 0
    sqrt_discriminant = sqrt(discriminant);
    t1 = (-b2 + sqrt_discriminant) / (2*a2);
    t2 = (-b2 - sqrt_discriminant) / (2*a2);
    intersections = [];
    if t1 >= 0 && t1 <= 1
        intersections = [intersections; a + t1*d];
    end
    if t2 >= 0 && t2 <= 1
        intersections = [intersections; a + t2*d];
    end
else
    intersections = [];
end
end

function intersection = intersectLineSegments(line1, line2)
% 求两条线段的交点
a1 = line1(1,:);
b1 = line1(2,:);
a2 = line2(1,:);
b2 = line2(2,:);
u = b1-a1;
v = b2-a2;
w = a1-a2;
d = u(1)*v(2) - u(2)*v(1);
if d == 0
    intersection = [];
else
    t = (v(1)*w(2) - v(2)*w(1)) / d;
    s = (u(1)*w(2) - u(2)*w(1)) / d;
    if t >= 0 && t <= 1 && s >= 0 && s <= 1
        intersection = a1 + t*u;
    else
        intersection = [];
    end
end
end

function path = connectPoints(points, obstacles)
% 将交点顺次连接起来，并避开障碍物
path = [];
if size(points,1) > 0
    % 找到最靠左的点作为起点
    [~,i] = min(points(:,1));
    current_point = points(i,:);
    path = [path; current_point];
    points(i,:) = [];
    % 沿着最靠左的点往右走，直到碰到障碍物为止
    while true
        next_point = current_point + [1, 0];
        intersections = intersectPolygons([current_point; next_point], obstacles);
        if size(intersections,1) > 0
            [~,i] = min(intersections(:,2));
            next_point = intersections(i,:);
        end
        path = [path; next_point];
        if next_point(1) >= max(points(:,1))
            break;
        end
        % 找到下一个交点
        [min_distance, i] = min(sqrt(sum((points - next_point).^2, 2)));
        if min_distance < inf
            current_point = points(i,:);
            points(i,:) = [];
        else
            % 没有交点了，直接往右走到最右边
            current_point = [max(points(:,1)), next_point(2)];
        end
        path = [path; current_point];
    end
end
end

这个算法的基本思路是，先将岛屿轮廓和圆形岛屿与一系列平行线求交，得到一些交点。然后从最靠左的交点开始，沿着最靠左的线往右走，碰到障碍物就拐弯，直到走到最右边。在每个拐角处，找到下一个交点，顺次连接起来，形成一条绕过障碍物的路径。