Fit a Weibull model with arms, cd40, age, wtkg, homo, race, gender as the explanatory variables. Compare the outputs of this Weibull model and Cox Model 1 in Assignment 3.我要R语言代码

好的，以下是对应的R语言代码，首先需要读入数据，假设数据集名为"mydata":

library(survival)

# Fit a Weibull model with arms, cd40, age, wtkg, homo, race, gender as the explanatory variables
weibull_model <- survreg(Surv(time, status) ~ arms + cd40 + age + wtkg + homo + race + gender, data = mydata, dist = "weibull")

# Print the summary of the Weibull model
summary(weibull_model)

# Fit Cox Model 1 from Assignment 3
cox_model1 <- coxph(Surv(time, status) ~ cd40 + age + wtkg + homo + race + gender, data = mydata)

# Print the summary of Cox Model 1
summary(cox_model1)

这里我们使用了`survreg()`函数来拟合Weibull模型，其中`Surv()`函数用于指定生存时间和事件信息的格式。`coxph()`函数则用于拟合Cox模型，这个函数在之前的作业中已经使用过了。最后我们使用`summary()`函数来打印模型的结果摘要。

需要注意的是，我们在Weibull模型中指定了分布类型为"Weibull"，而Cox模型中则不需要指定分布类型。