用Python编程:已知有演员8人，导演4人，电影9部，现随机给每部电影分配4个演员和一个导演，现查找关系最好的两个演员以及他们共同参演的电影和电影的导演，并输出。这里假设，如果某两个演员共同参演电影的数量最多，那么这二人关系最好。运行结果示例： 电影1: [导演1，演员1，演员2，演员3，演员4] 电影2: [导演3，演员4，演员3，演员1，演员5] …… 关系最好的两个演员是：（演员1，演员2） 共同参演的电影和导演是：(电影1，导演1)

我可以回答这个问题。以下是Python代码实现：

import random

actors = ['演员1', '演员2', '演员3', '演员4', '演员5', '演员6', '演员7', '演员8']
directors = ['导演1', '导演2', '导演3', '导演4']
movies = ['电影1', '电影2', '电影3', '电影4', '电影5', '电影6', '电影7', '电影8', '电影9']

movie_cast = {}
for movie in movies:
movie_cast[movie] = [random.choice(directors)]
for i in range(4):
actor = random.choice(actors)
while actor in movie_cast[movie]:
actor = random.choice(actors)
movie_cast[movie].append(actor)

actor_movies = {}
for actor in actors:
actor_movies[actor] = []
for movie in movie_cast:
if actor in movie_cast[movie]:
actor_movies[actor].append(movie)

best_actors = ('', '')
best_movies = []
best_directors = []

for i in range(len(actors)):
for j in range(i+1, len(actors)):
common_movies = set(actor_movies[actors[i]]) & set(actor_movies[actors[j]])
if len(common_movies) > len(set(best_movies)):
best_actors = (actors[i], actors[j])
best_movies = list(common_movies)
best_directors = [movie_cast[movie][] for movie in best_movies]

print('关系最好的两个演员是：（{}，{}）'.format(best_actors[], best_actors[1]))
print('共同参演的电影和导演是：')
for i in range(len(best_movies)):
print('{}: [{}, {}, {}, {}, {}]'.format(best_movies[i], best_directors[i],
best_actors[], best_actors[1],
random.choice(actors), random.choice(actors)))