用C语言写一个求集合交集和并集的代码

#include <stdio.h>

int main() {
    int set1[100], set2[100], intersection[100], unionset[200];
    int n1, n2, i, j, k, unionlen = 0, intersectionlen = 0;

    printf("请输入第一个集合的元素个数：");
    scanf("%d", &n1);
    printf("请输入第一个集合的元素：");
    for (i = 0; i < n1; i++) {
        scanf("%d", &set1[i]);
        unionset[unionlen++] = set1[i];
    }

    printf("请输入第二个集合的元素个数：");
    scanf("%d", &n2);
    printf("请输入第二个集合的元素：");
    for (i = 0; i < n2; i++) {
        scanf("%d", &set2[i]);
        unionset[unionlen++] = set2[i];
    }

    // 求并集
    for (i = 0; i < unionlen; i++) {
        for (j = 0; j < i; j++) {
            if (unionset[i] == unionset[j]) {
                break;
            }
        }
        if (j == i) {
            // 没有重复的元素
            printf("%d ", unionset[i]);
        }
    }
    printf("是两个集合的并集\n");

    // 求交集
    for (i = 0; i < n1; i++) {
        for (j = 0; j < n2; j++) {
            if (set1[i] == set2[j]) {
                intersection[intersectionlen++] = set1[i];
                break;
            }
        }
    }
    printf("两个集合的交集为：");
    for (i = 0; i < intersectionlen; i++) {
        printf("%d ", intersection[i]);
    }
    printf("\n");

    return 0;
}