使用C语言研发一个人机交互的棒子老虎鸡的游戏！游戏规则是：棒子打老虎，老虎吃鸡，鸡吃虫，虫吃棒子！要求游戏生动形象，每10次给一个输赢统计！ 代码

好的，以下是一个简单的棒子老虎鸡游戏的C语言代码。请注意，为了简化代码，以下实现没有使用ASCII艺术字符，而是使用了简单的文字表示棒子、老虎、鸡、虫四种动物的形象。

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

int main() {
    int player_choice, computer_choice, player_win = 0, computer_win = 0, round = 0;
    srand((unsigned int)time(NULL)); // 用当前时间初始化随机数发生器

    printf("Welcome to the Stick-Tiger-Chicken-Insect game!\n");
    printf("In this game, Stick beats Tiger, Tiger eats Chicken, Chicken eats Insect, Insect beats Stick.\n");
    printf("You will play against the computer. Let's start!\n\n");

    do {
        round++;
        printf("Round %d:\n", round);

        // 生成电脑随机选择的动物
        computer_choice = rand() % 4 + 1;

        // 让玩家输入自己选择的动物
        printf("Enter your choice (1 for Stick, 2 for Tiger, 3 for Chicken, 4 for Insect): ");
        scanf("%d", &player_choice);

        // 判断玩家和电脑的胜负关系
        if (player_choice == computer_choice) {
            printf("Draw!\n");
        } else if ((player_choice == 1 && computer_choice == 4) || (player_choice == 2 && computer_choice == 1) ||
                   (player_choice == 3 && computer_choice == 2) || (player_choice == 4 && computer_choice == 3)) {
            printf("You win!\n");
            player_win++;
        } else {
            printf("Computer wins!\n");
            computer_win++;
        }

        // 每10次游戏结束后打印胜负次数统计
        if (round % 10 == 0) {
            printf("You won %d times and the computer won %d times in the last 10 rounds.\n", player_win, computer_win);
            player_win = 0;
            computer_win = 0;
        }

        printf("\n");
    } while (1);

    return 0;
}

希望这个代码对您有帮助！