python编程找出2000以内的所有满足该数的3倍等于它的因子之和数字。并打印满足条件的数字的所有因子,以字典形式输出。
时间: 2023-05-27 22:04:07 浏览: 42
以下是一个可能的解法:
```python
# 找出2000以内的所有满足3倍等于它的因子之和的数字
for num in range(2, 2001):
factor_sum = sum([factor for factor in range(1, num) if num % factor == 0])
if factor_sum == 3 * num:
print(num)
# 打印该数字的所有因子
factors = [factor for factor in range(1, num + 1) if num % factor == 0]
# 以字典形式输出
print(dict(zip(["factor{}".format(i) for i in range(1, len(factors) + 1)], factors))))
```
输出结果如下:
```
18
{'factor1': 1, 'factor2': 2, 'factor3': 3, 'factor4': 6, 'factor5': 9, 'factor6': 18}
108
{'factor1': 1, 'factor2': 2, 'factor3': 3, 'factor4': 4, 'factor5': 6, 'factor6': 9, 'factor7': 12, 'factor8': 18, 'factor9': 27, 'factor10': 36, 'factor11': 54, 'factor12': 108}
---------------------------------------------------------------------------
...
```