Initialize TIM3 peripheral as follow: + Period = 10000 - 1 + Prescaler = ((SystemCoreClock/2)/10000) - 1 + ClockDivision = 0 + Counter direction = Up是什么意思
时间: 2024-02-14 21:22:46 浏览: 31
这段话的意思是要对TIM3外设进行初始化,具体的初始化参数如下:
+ 定时器周期为10000-1,即每个周期为1ms;
+ 分频值为((SystemCoreClock/2)/10000)-1,即将系统时钟分频为10KHz,用于定时器的计数;
+ 时钟分频为0,即不分频;
+ 计数器方向为向上计数。
这些参数的意义如下:
+ 定时器周期:每个定时器周期的时间长度,例如这里的10000-1表示一个定时器周期为1ms;
+ 分频值:用于将时钟信号分频,例如这里的((SystemCoreClock/2)/10000)-1表示将系统时钟分频为10KHz,用于定时器的计数;
+ 时钟分频:用于将时钟信号再次分频,例如这里的时钟分频为0,即不分频;
+ 计数器方向:定时器的计数器可以向上计数或向下计数,例如这里的向上计数表示从0开始计数,计数值会逐渐增加直至达到定时器周期。
相关问题
int x=2,y=3,z;z=(++x>=y--)?((--y==1)?x--:--y):y--;过程
1. x=2, y=3, z; // initialize variables
2. y--; // post-decrement y, y=2
3. x>=y--; // compare x (2) with the post-decremented y (2), returns true
4. (--y==1)?x--:--y // pre-decrement y (1), check if it's equal to 1, it is, so x is decremented (x=1)
5. z = x--; // assign x to z, then decrement x (z=1, x=0)
6. Answer: z=1, x=0, y=1
帮我生成这个代码的流程图:a1,b1,c1=input().split(" ") a2,b2,c2=input().split(" ") a1=int(a1) b1=int(b1) c1=int(c1) a2=int(a2) b2=int(b2) c2=int(c2) d1=[0,31,28,31,30,31,30,31,31,30,31,30,31] d2=[0,31,29,31,30,31,30,31,31,30,31,30,31] sum=0 def leapyear(x): if x%400==0 or (x%4==0 and x%100!=0): return True else: return False def cha(x,x1,x2): cum=0 if leapyear(x): for i in range(x1,x2): cum+=d2[i] else: for i in range(x1,x2): cum+=d1[i] return cum if a1==a2: if b1==b2: if c1==c2: sum+=0 else: sum+=(c2-c1) else: sum+=(cha(a1,b1,b2)+c2-c1) else: sum+=(cha(a1,b1,12)+31-c1+cha(a2,1,b2)+c2-1+1) week=sum//7+1 weekdays=sum%7+1 print(f"{week} {weekdays}")
好的,以下是代码流程图:
```
+------------------------+
| Start |
+------------------------+
|
+------------------------+
| Input a1,b1,c1 |
+------------------------+
|
+------------------------+
| Input a2,b2,c2 |
+------------------------+
|
+------------------------+
| Convert a1,b1,c1 to int |
+------------------------+
|
+------------------------+
| Convert a2,b2,c2 to int |
+------------------------+
|
+------------------------+
| Initialize d1,d2,sum |
+------------------------+
|
+------------------------+
+------------>| Define leapyear function |
| +------------------------+
| |
| +------------------------+
| | Define cha function |
| +------------------------+
| |
+-------------+---------------------------+
| If a1==a2 |
| If b1==b2 |
| If c1==c2 |
| sum+=0 |
| Else |
| sum+=(c2-c1) |
| Else |
| sum+=(cha(a1,b1,b2)+c2-c1) |
| Else |
| sum+=(cha(a1,b1,12)+31-c1+cha(a2,1,b2)+c2-1+1) |
+------------------------+
|
+------------------------+
| Calculate week |
+------------------------+
|
+------------------------+
| Calculate weekdays |
+------------------------+
|
+------------------------+
| Output week and weekdays |
+------------------------+
|
+------------------------+
| End |
+------------------------+
```
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